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Lời giải:
\(S=\frac{1}{5}+\frac{2}{5^2}+\frac{3}{5^3}+...+\frac{2012}{5^{2012}}\)
\(\Rightarrow 5S=1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{2012}{5^{2011}}\)
Trừ theo vế:
\(4S=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2011}}-\frac{2012}{5^{2012}}\)
\(20S=5+1+\frac{1}{5}+...+\frac{1}{5^{2010}}-\frac{2012}{5^{2011}}\)
Trừ theo vế:
\(16S=5-\frac{2012}{5^{2011}}-\frac{1}{5^{2011}}+\frac{2012}{5^{2012}}\)
\(16S=5-\frac{2013}{5^{2011}}+\frac{2012}{5^{2012}}< 5-\frac{2013}{5^{2011}}+\frac{2013}{5^{2011}}=5\)
\(S< \frac{5}{16}< \frac{1}{3}\)
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A - B =(1 + 1/3 + 1/5 + 1/7 + ... + 1/2009 +1/2011) - (1/2 + 1/4 + 1/6 + ... + 1/2010 + 1/2012 )
A - B = 1 + 1/3 + 1/5 + 1/7 + ... + 1/2009 +1/2011 - 1/2- 1/4 - 1/6 - ... - 1/2010 1/2012
A - B = 1 - 1/2 + 1/3 - 1/4 + 1/5 - 1/6 +..... 1/2011 - 1/2012
A - B = 1/ 1.2 + 1/3.4 + 1/5.6 + .... + 1/2011. 2012
A - B = 1 - 1 / 2012 = 2011 /2012 < 1
Vậy A - B < 1