Question

[Sarah]

Cho hàm số \(y=f\left(x\right)=3x^2+1\). Tính : \(f\left(\frac{1}{2}\right)\) ; \(f\left(1\right)\) ; \(f\left(3\right)\)

Answer 1

[Trà My]

• \(f\left(\frac{1}{2}\right)=3.\left(\frac{1}{2}\right)^2+1=3.\frac{1}{4}+1=\frac{3}{4}+1=\frac{7}{4}\)
• \(f\left(1\right)=3.1^2+1=3.1+1=3+1=4\)
• \(f\left(3\right)=3.3^2+1=3^3+1=27+1=28\)