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![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(a+11-a-29=\left(a-a\right)+\left(11-29\right)=-18\)
b) \(a-b-22+25+b=a+\left(b-b\right)+\left(25-22\right)=a+3=\)
\(=\left(-25\right)+3=-22\)
c) \(b-5+a-6-c+7-a+9=\left(a-a\right)+b-c+\left(9+7-5-6\right)\)
\(=b-c+5=14-\left(-15\right)+5=14+15+5=34\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 :
a, 25 + (-42) = - ( 42 - 25 ) = - 17
b, (-17) + 5 + 8 + 17 + (-3 )
= [ (-17) + 17 ] + [ ( 5 + 8 ) + (-3) ]
= 0 + 10
= 10
c, 25. 22 - ( 15-18 ) + ( 12 - 19 + 10 )
= 25 . 4 - (-3) + 3
= 100 - [ (-3) + 3 ]
= 100 - 0
= 100
d, 120 - 35 + 29 - 242
= 85 + 29 - 242
= 114 - 242
= -128
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3:
a: A=-5-7-8=-20
b: =-3+7+2*(-8)=-16+4=-12
c: =2-3*15-8=-55
Bài 4:
a: x-y+2=-12-25+2=-37+2=-35
b: x+y+z-y-3=x+z-3=-12-15-3=-30
c: =20-12-(25-15)+12=20-10=10
d: =25-(-12+25+15)+3
=25+12-25-15-3
=-3-3=-6
![](https://rs.olm.vn/images/avt/0.png?1311)
a)-1+2-3+11-17+18
=(11-1)+(18-3)-(17-2)
=10+6-15=1
b)-(3-4+5)+(-15-6-7)
=-(4)+(-28)=-4-28=-33(quy tắc dấu ngoặc)
c)(a-b+c)-(b-c-a)
=a+b+c-b+c+a(quy tắc dấu ngoặc)
=2a+2c
d)-(-a-b-c)+(-b-c+a)
=a+b+c-b-c+a(quy tắc dấu ngoặc)
=2a
=
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A= (b+a)+(c+d)-(c+a)-(c+b)
A= b+a+c+d-c-a-c-b
A=(b-b) +(a-a)+(c-c-c)+d
A=0+0-c+d
A=-c+d
B=(a-b)-(d+a)-(c-d)+(c+d)
B=a-b-d-a-c+d+c+d
B=(a-a)+(b-b)+(c-c)+(d-d)
B=0+0+0+0
B=0
B