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a. 32.(x-10)=32
x-10=32:32
x-10=1
x =1+10
x =11
b. (x-105):21=15
x-105 =15.21
x-105 =315
x =315+105
x =420
c. (x-5).(x-7)=0
x-5=0 hay x-7=0
x =0+5 hay x =0+7
x =5 hay x =7
a, 32 . ( x - 10 ) = 32
x - 10 = 32 : 32
x - 10 = 1
x = 10 + 1
x = 11
b, ( x - 105 ) : 21 = 15
x - 105 = 15 . 21
x - 105 = 315
x = 315 + 105
x = 420
c, ( x - 5 ) . ( x - 7 ) = 0
x - 5 = 0
x = 5
x - 7 = 0
x = 7
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a) \(x-2=-6\)
\(x=-6+2\)
\(x=-4\)
b) \(15-\left(x-7\right)=-21\)
\(x-7=36\)
\(x=43\)
c) \(4.\left(3x-4\right)-2=18\)
\(4\left(3x-4\right)=20\)
\(3x-4=5\)
\(3x=9\)
\(x=3\)
d) \(\left(3x-6\right)+3=32\)
\(3x-6=29\)
\(3x=29+6\)
\(3x=35\)
\(x=\frac{35}{3}\)
e) \(\left(3x-6\right).3=32\)
\(3x-6=\frac{32}{3}\)
\(3x=\frac{32}{3}+6\)
\(3x=\frac{50}{3}\)
\(x=\frac{50}{9}\)
f) \(\left(3x-6\right):3=32\)
\(3x-6=96\)
\(3x=102\)
\(x=34\)
g) \(\left(3x-6\right)-3=32\)
\(3x-6=35\)
\(3x=41\)
\(x=\frac{41}{3}\)
h) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right)=2.7=14\)
\(\left(3x-16\right)=14\)
\(3x=14+16=30\)
\(x=10\)
i) \(\left|x\right|=\left|-7\right|\)
\(\left|x\right|=7\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
k) \(\left|x+1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}}\)
l) \(\left|x-2\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
m) \(x+\left|-2\right|=0\)
\(x+2=0\)
\(x=-2\)
o) \(72-3\left|x+1\right|=9\)
\(3\left|x-1\right|=63\)
\(\left|x-1\right|=21\)
\(\Rightarrow\orbr{\begin{cases}x-1=21\\x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-20\end{cases}}}\)
p) Ta có: \(\left|x-1\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}}\)
mà \(x+1< 0\)
\(\Rightarrow x-1=-3\)
\(\Rightarrow x=-2\)
q) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}}\)
hok tốt!!
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a, 10 + 2x = 45 ÷ 43
10 + 2x = 45/43
2x = 45/43 - 10
2x = -385/43
x = -385/43 ÷ 2
x = -385/86
b, 2x - 138 = 23.32
2x - 138 = 736
2x = 736 + 138
2x = 874
x = 874 ÷ 2
x = 437
c, 231 - ( x - 6 ) = 1339 ÷ 13
231 - ( x - 6 ) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
d, x + 5.2 - ( 32 + 16.3 ÷ 6 - 15 ) = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
a) 10 + 2 . x = 45 : 43
2 . x = 45/43 -10
2 . x = -385/43
x = -385/43 : 2
x = -385/86
b) 2 . x - 138 = 23 . 32
2 . x - 138 = 736
2 . x = 736+138
2 . x = 874
x = 874 : 2
x = 437
c) 231 - (x -6) = 1339 : 13
231 - (x -6) = 103
x - 6 = 231 -103
x - 6 = 98
x = 98 +6
x = 104
d) x + 5 . 2 - (32 +16 . 3 : 6 - 15) = 0
x + 5 . 2 - (32 + 48 : 6 - 15) = 0
x + 5 . 2 - (32 + 8 - 15) = 0
x + 5 . 2 - 25 = 0
x + 10 - 25 = 0
x + 10 = 0 + 25
x + 10 = 25
x = 25 - 10
x = 15
![](https://rs.olm.vn/images/avt/0.png?1311)
|\(x-5\)| = 7
\(\left[{}\begin{matrix}x-5=-7\\x-5=7\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-2\\x=12\end{matrix}\right.\)
\(x\in\) {-2; 12}
Có hai giá trị \(x\) thỏa mãn. Vậy chọn C.2
Chọn C
− 21 . x − 32 = 0 ⇔ x − 32 = 0 ⇔ x = 32