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![](https://rs.olm.vn/images/avt/0.png?1311)
1. 2Al + 3O2 \(\rightarrow\) 2AlCl3
tỉ lệ 2:3:2
2. 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3
tỉ lệ 2:3:2
3. 2Na + 2H2O \(\rightarrow\) 2NaOH + H2
tỉ lệ 2:2:2
4. Zn + 2HCl \(\rightarrow\) ZnCl2 + H2
tỉ lệ 1:2:1:1
5. 2CxHy + (2x+y/2)O2 \(\rightarrow\) 2xCO2 + yH2O
tỉ lệ 2:(2x+y/2):2x:y
6.P2O5 + 3H2O \(\rightarrow\) 2H3PO4
tỉ lệ 1:3:2
7. Fe2(SO4)3 + 6KOH \(\rightarrow\) 2Fe(OH)3 + 3K2SO4
tỉ lệ 1:6:2:3
8. 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3
tỉ lệ 2:3:2
9. 2CnH2n-2 + (n-1)O2 \(\rightarrow\) 2nCO2 + 2(n-1)H2O
tỉ lệ 2:(n-1):2n:2(n-1)
10. N2O5 + H2O \(\rightarrow\) 2HNO3
tỉ lệ 1:1:2
11. FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + NaCl
tỉ lệ 1:3:1:1
12. 2Al + 3Cl2 \(\rightarrow\) 2AlCl3
tỉ lệ 2:3:2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2C_xH_yO_z+\dfrac{4x+y-2z}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)
\(2C_xH_yO+\dfrac{4x+y-2}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)
\(6Fe_xO_y+\left(12x-2y\right)H_2SO_{4\left(đ\right)}\underrightarrow{t^o}3xFe_2\left(SO_4\right)_3+\left(3x-2y\right)S+\left(12x-2y\right)H_2O\)
\(8Fe_xO_y+\left(30x-4y\right)HNO_3\rightarrow8xFe\left(NO_3\right)_3+\left(3x-2y\right)N_2O+\left(15x-2y\right)H_2O\)
2 PTHH đầu mình cân bằng như bth, 2 PTHH cuối mình dùng phương pháp electron
![](https://rs.olm.vn/images/avt/0.png?1311)
$\rm k)2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2 \uparrow$
$\rm l)CH_4 + 2O_2 \xrightarrow{t^o} CO_2 + 2H_2O$
$\rm m)2Al + 3H_2SO_4 \rightarrow Al_2(SO_4)_3 + 3H_2 \uparrow$
$\rm n)Na_2CO_3 + CaCl_2 \rightarrow CaCO_3 \downarrow + 2NaCl$
$\rm o)2Na + 2H_2O \rightarrow 2NaOH + H_2 \uparrow$
$\rm p)CaO + 2HNO_3 \rightarrow Ca(NO_3)_2 + H_2O$
$\rm q)P_2O_5 + 3H_2O \rightarrow 2H_3PO_4$
$\rm r)Zn + 2HCl \rightarrow ZnCl_2 + H_2 \uparrow$
$\rm s)4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3$
$\rm t)Ba(OH)_2 + 2HCl \rightarrow BaCl_2 + 2H_2O$
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3Fe+2O_2\rightarrow Fe_3O_4\)
b) \(Fe_3O_4+8HCl\rightarrow FeCl_2+2FeCl_3+4H_2O\)
c) \(2NaHCO_3\rightarrow Na_2CO_3+CO_2+H_2O\)
d) \(2C_2H_2+5O_2\rightarrow4CO_2+2H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(K_2O+H_2O->2KOH\)
b) \(2Fe+3Cl_2->2FeCl_3\)
c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)
d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)
e)\(2Al+6HCl->2AlCl_3+3H_2\)
f) \(2KClO_3->KCl+3O_2\)
g) \(4P+5O_2->2P_2O_5\)
h) \(3Fe+2O_2->Fe_3O_4\)
i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)
j) \(2K+2H_2O->2KOH+H_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(n_{H_2O}=\dfrac{1.8}{18}=0.1\left(mol\right)\)
\(C_2H_2+\dfrac{5}{2}O_2\underrightarrow{t^0}2CO_2+H_2O\)
\(0.1.........0.25......0.2..........0.1\)
\(V_{C_2H_2}=2.24\left(l\right)\)
\(V_{O_2}=0.25\cdot22.4=5.6\left(l\right)\)
\(V_{CO_2}=0.2\cdot22.4=4.48\left(l\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1,Fe3O4+8HCl−−>FeCl2+2FeCl3+4H2O
2, 2Cu(NO3)2−−>2CuO+4NO2+O2
3, 2K+2H2O−−>2KOH+H2
4,2A+2xH2O−−>2A(OH)x+xH2
5, 2C4H10+13O2−−>8CO2+10H2O
6,C2H4O2+2O2−−>2CO2+2H2O
7,2KClO3−−>2KCl+3O2
8,2KNO3−−>2KNO2+O2
![](https://rs.olm.vn/images/avt/0.png?1311)
1) 2CnH2n+3nO2→2nCO2+2nH2O
2) CnH2n + 2 + \(\dfrac{3n+1}{2}\) O2 -> nCO2 + (n+1)H2O.
3) CnH2n – 2 + \(\dfrac{3n-1}{2}\) O2 -> nCO2 +(n-1) H2O.
4) CnH2n-6 +\(\dfrac{3n-3}{2}\) O2 -> nCO2 + (n-3) H2O
5) CnH2n+2O+\(\dfrac{3n}{2}\)O2→nCO2+(n+1)H2O
6) 2CxHyOz + \(\dfrac{4x+y-2z}{2}\) O2 →2x CO2 + yH2O
7) CxHyOzNt + \(\left(x+\dfrac{y}{4}\right)-\dfrac{z}{2}\)O2→xCO2+\(\dfrac{y}{2}\)H2O + \(\dfrac{t}{2}\) N2
a,C2H2+\(\dfrac{5}{2}\)O2->2CO2+H2O
b,3NaOH+FeCl3->Fe(OH)3+3NaCl
c,C2H4+3O2->2CO2+2H2O