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\(BCNN\left(20,30\right)=60\\ BCNN\left(84,108\right)=756\\ BCNN\left(45,150\right)=450\\ BCNN\left(12,15,10\right)=60\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có :
132=22.3.11
234=.32.13
=>BCNN(132;234)=22.32.11.13=5148
=>UCLN(132;234)=2.3=6
Ta có: 132 = 22.3.11
234 = 2.32.13
=> BCNN(132;234) = 22.32.11.13 = 5148
Vậy BCNN(132;234) = 5148
![](https://rs.olm.vn/images/avt/0.png?1311)
84=22.3.7
108=22.33
=>BCNN(84,108)=22.33.7=756
24=23.3
40=23.5
168=23.3.7
=>BCNN(24,40,168)=23.3.5.7=840
ta có 84=22.3.7
108= 22.33
=>BCNN(84,108)=22.33.7=756
ta có 24=23.3
40=23.5
168=23.3.7
=>BCNN(24,40,168)=23.3.5.7=840
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có: 24 = 2 3 . 3 ; 10 = 2.5
=> ƯCLN(24;10) = 2
BCNN(24;10) = 2 3 . 3 .5 = 120
b, Ta có: 150 = 2 . 3 . 5 2 ; 84 = 2 2 . 3 . 7
=> ƯCLN(150;84) = 2.3 = 6
BCNN(150;84) = 2 2 . 3 . 5 2 . 7
c, Ta có: 140 = 2 2 . 5 . 7 ; 210 = 2.3.5.7; 56 = 2 3 . 7
=> ƯCLN(140;210;56) = 2.7 = 14
BCNN(140;210;56) = 2 3 . 3 . 5 . 7 = 840
d, Ta có: 105 = 3.5.7; 84 = 2 2 . 3 . 7 ; 30 = 2.3.5
=> ƯCLN(105;84;30) = 3
BCNN(105;84;30) = 2 2 . 3 . 5 . 7 = 420
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có 84=22.3.784=22.3.7;
108=22.33108=22.33
BCNN(84,108)=22.33.7=756BCNN(84,108)=22.33.7=756.
b) 13=1313=13
15=3.515=3.5
BCNN(13,15)=3.5.13=195BCNN(13,15)=3.5.13=195.
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