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Đặt \(A=\frac{1995x1994-1}{1995x1993+1994}=\frac{1995x\left(1993+1\right)-1}{1995x1993+1994}=\frac{1995x1993+1995-1}{1995x1993+1994}=\frac{1995x1993+1994}{1995x1993+1994}=1\)
Vậy A = 1
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A 16X5X9X3X4/3X5X16X9X4=1/1=1
B 1996X1995-1996X1/1994X1+1995X1994
=1995X(1996-1)/1995X(1994+1)=1995X1995/1995X1995
=1/1=1
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a) \(\frac{2005.2007-1}{2004+2005.2006}=\frac{\left(2014+1\right).2007-1}{2004+2005.2006}=\frac{2004+2005.2007-1}{2004+2005-2006}=\frac{2004+2005.2006}{2004+2005.2006}=1\)
a) 2005*2007-1 b)2003*2004+2005*10+1994
2004+2005*2006 2005*2004-2003*2004
c) ( 5+3/8+18+1/2-7-5/24 )
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c) 5 + \(\frac{3}{8}\)+18 + \(\frac{1}{2}\) - 7 - \(\frac{5}{24}\)
=\(\frac{43}{8}\)+ \(\frac{35}{2}\) +\(\frac{163}{24}\)
=\(\frac{129}{24}\)+ \(\frac{420}{24}\)+\(\frac{163}{24}\)
= \(\frac{58}{51}\)
k nhé
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1995 * 1994 - 1 / 1993 * 1995 + 1994
= 1995 * 1994 - 1 / ( 1994 -1 ) * 1995 + 1994
= 1995 * 1994 - 1 / 1994 * 1995 - 1995 + 1994
= 1995 * 1994 - 1 / 1994 * 1995 - 1
= 1
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A= 2006*2010-2005 / 2007*2009-2008
A=4032060-2005 / 4032063-2008
A=4030055/4030055
A=1
Lời giải:
a.
\(\frac{2008\times 2009-2}{2007\times 2009+2007}=\frac{2009\times (2007+1)-2}{2007\times 2009+2007}\\ =\frac{2009\times 2007+2007}{2007\times 2009+2007}=1\)
b.
\(\frac{1995\times 1994-1}{1993\times 1995+1994}=\frac{1995\times (1993+1)-1}{1995\times 1993+1994}\\ =\frac{1995\times 1993+1994}{1995\times 1993+1994}\\ =1\)