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\(a,x-\frac{1}{4}=\frac{5}{8}\times\frac{2}{3}\)
\(x-\frac{1}{4}=\frac{5}{12}\)
\(x=\frac{5}{12}+\frac{1}{4}\)
\(x=\frac{2}{3}\)
\(b,\frac{x}{126}=-\frac{5}{9}\times\frac{4}{7}\)
\(\frac{x}{126}=-\frac{20}{63}\)
\(\Rightarrow63\times x=\left(-20\right)\times126\)
\(\Rightarrow63\times x=-2520\)
\(\Rightarrow x=\left(-2520\right):63\)
\(\Rightarrow x=-40\)
\(a,x-\frac{1}{4}=\frac{5}{8}\cdot\frac{2}{3}\)
\(x-\frac{1}{4}=\frac{5}{12}\)
\(\Rightarrow x=\frac{5}{12}+\frac{1}{4}\)
\(x=\frac{2}{3}\)
\(b,\frac{x}{126}=-\frac{5}{9}\cdot\frac{4}{7}\)
\(\frac{x}{126}=-\frac{20}{63}\)
\(\Rightarrow63\cdot x=\left(-20\right)\cdot126\)
\(\Rightarrow x=\left(2520\right):63\)
\(x=-40\)
a) Thiếu đề nhé
b) \(\left|x\right|-5=3\Leftrightarrow\left|x\right|=8\Leftrightarrow x=+_-8\)
c) \(\left|x-3\right|=7-\left(-2\right)\Leftrightarrow\left|x-3\right|=9\Leftrightarrow\orbr{\begin{cases}x-3=9\\x-3=-9\end{cases}\Leftrightarrow\orbr{\begin{cases}x=12\\x=-6\end{cases}}}\)
b)|x|-5=3
|x|=3+5
|x|=8
suy ra x=8 hoặc x=-8
c) |x-3|=7-(-2)
|x-3|=9
suy ra x-3=9 hoặc x-3=-9
x=9+3 x=-9+3
x=12 x=-6
vậy x=12 hoặc x=-6
ý a thiếu đầu bài nha
Giải:
a) \(2\dfrac{17}{20}-1\dfrac{15}{11}+6\dfrac{9}{20}:3\)
\(=\dfrac{57}{20}-\dfrac{26}{11}+\dfrac{129}{20}:3\)
\(=\dfrac{107}{220}+\dfrac{43}{20}\)
\(=\dfrac{29}{11}\)
b) \(4\dfrac{3}{7}:\left(\dfrac{7}{5}.4\dfrac{3}{7}\right)\)
\(=\dfrac{31}{7}:\left(\dfrac{7}{5}.\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}\)
\(=\dfrac{5}{7}\)
c) \(\left(3\dfrac{2}{9}.\dfrac{15}{23}.1\dfrac{7}{29}\right):\dfrac{5}{23}\)
\(=\left(\dfrac{29}{9}.\dfrac{15}{23}.\dfrac{36}{29}\right):\dfrac{5}{23}\)
\(=\dfrac{60}{23}:\dfrac{5}{23}\)
\(=12\)
a) 5.3x = 405
3x = 81 = 34
=> x = 4
b) 2x : 8 = 4
2x = 32 = 25
=> x = 5
c) x64 = x
=> x64 - x = 0
x.(x63 -1) = 0
=> x = 0
x63 - 1 = 0 => x63 = 1 => x = 1
KL: ...
phần d lm tương tự phần c nha bn
e) (x-2)5 = 243 = 35
=> x - 2 = 3
x = 5
g) (x+1)3 = 125 = 53
=> x + 1 = 5
x = 4
1a)1+2+3+...+x=0
\(\frac{x.\left(x+1\right)}{2}\)=0
x.(x+1) =0:2
x.(x+1) =0
x.(x+1) =0.1
vây x=0
tich dung cho minh nha
a;x=2/3
b=x=-40 nhớ k nha
ta có:\(x-\frac{1}{4}=\frac{5}{8}\cdot\frac{2}{3}\)
=>\(x-\frac{1}{4}=\frac{5}{12}\)
=>\(\frac{2}{3}\)
b)\(\frac{x}{126}=\frac{-20}{63}\)
=>\(\frac{x}{126}=\frac{-40}{126}\)
=>x=-40