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a: \(=\dfrac{7\cdot5+3\cdot9}{45}\cdot\dfrac{2}{3}=\dfrac{62}{45}\cdot\dfrac{2}{3}=\dfrac{124}{135}\)
b: \(=\dfrac{6}{11}\cdot\dfrac{5}{7}=\dfrac{30}{77}\)
c: \(=\dfrac{7}{8}\cdot\dfrac{8-3}{9}=\dfrac{7}{8}\cdot\dfrac{5}{9}=\dfrac{35}{72}\)
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\(\text{#TNam}\)
`a, (7/9+3/5) \times 2/3`
`C1:`
`=62/45 \times 2/3`
`= 124/135`
`C2:`
`= 7/9 \times 2/3 + 3/5 \times 2/3`
`= 14/27 +2/5`
`= 124/135`
`b, `
`C1:`
`= 6/11 \times 5/7`
`=`30/77`
`C2:
`= 9/11 \times 5/7-3/11 \times 5/7`
`= 45/77 -15/77`
`= 30/77`
`c,`
`C1:`
`= 7/8 \times 5/9`
`=35/72`
`C2:`
`= 7/8 \times 8/9- 7/8 \times 1/3`
`= 7/9-7/24`
`=35/72`
a)5/8 + 3/8 : 2/3
=5/8 + 9/16
=19/16
b)3/5 x 5/7 +1/11
=3/7+ 1/11
=40/77
1:
a: =8/7-5/88=669/616
b: \(=1+\dfrac{2}{9}\cdot\dfrac{3}{7}-\dfrac{10}{7}=1+\dfrac{2}{21}-\dfrac{10}{7}\)
\(=\dfrac{21+2-30}{21}=\dfrac{-7}{21}=\dfrac{-1}{3}\)
c: \(=\dfrac{11}{3}-\dfrac{6}{7}+4=\dfrac{77-18+84}{21}=\dfrac{143}{21}\)
Bài 2:
a: =>9/4-x=5/11*2=10/11
=>x=9/4-10/11=59/44
b: =>2/9:x=19/21
=>x=2/9:19/21=14/57
\(a,\dfrac{5}{9}+\dfrac{3}{8}=\dfrac{40}{72}+\dfrac{27}{72}=\dfrac{67}{72}\)
\(b,\dfrac{8}{12}-\dfrac{1}{3}=\dfrac{8}{12}-\dfrac{4}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)
\(c,\dfrac{4}{7}\times\dfrac{5}{2}=\dfrac{20}{14}=\dfrac{10}{7}\)
\(d,\dfrac{5}{11}:\dfrac{15}{22}=\dfrac{5}{11}\times\dfrac{22}{15}=\dfrac{110}{165}=\dfrac{22}{33}\)
a) \(27900:\left(11+8\right)+13700\)
\(=27900:19+13700\)
\(=1468+13700=15168\)
b) \(400940-28005\times5\)
\(=400940-140025=260915\)