![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 2x=138+72\(\Leftrightarrow\)2x=210\(\Rightarrow\)x=105
b) 237-x=103\(\Rightarrow\)x=237-103=134
c) 6x+8=50\(\Leftrightarrow\)6x=50-8=42\(\Rightarrow\)x=42:6=7
![](https://rs.olm.vn/images/avt/0.png?1311)
123-5.(x+4)=38
5(x+4)=123-38
5(x+4)=85
x+4=85:5
x+4=17
x=17-4
x=13
10+2x=2.(32-1)
10+2x=2.(9-1)
10+2x=2.8
2x=16-10
2x=6
x=6:2
x=3
2.x-138=23.32
2.x-138=72
2.x=72+138
2.x=210
x=210:2
x=105
[102+(28-2x)]:20-5=1
(102+28-2x):20=6
130-2x=120
2x=130-120
2x=10
x=10:2
x=5
231-(x-6)=1339:13
231-(x-6)=103
x-6=231-103
x-6=128
x=128+6
x=134
123-5.(x+4)=38
5.(x+4)=123-38
5.(x+4)=85
(x+4)=85/5
x+4=17
x=17-4
x=13
![](https://rs.olm.vn/images/avt/0.png?1311)
a)13-2(x+1)=7
2.(x+1)=13-7
2.(x+1)=6
x+1=6/2
x+1=3
x=3-1
x=2
a, 13 - 2 ( x + 1 ) = 7
2 .( x + 1 ) = 13 - 7
2 .( x + 1 ) = 6
x + 1 = 6 : 2
x + 1 = 3
x = 3 - 1
x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.2.x-138=2^3.3^2\)
\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x\) \(=72+138\)
\(2.x\) \(=210\)
\(x\) \(=210:2\)
\(x\) \(=105\)
\(b.231-\left(x-6\right)=1339:13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x\) \(=128+6\)
\(x\) \(=134\)
\(c.\left[\left(6.x-72\right):2-84\right].28=5628\)
\(\left[\left(6.x-72\right):2-84\right]\) \(=5628:28\)
\(\left(6.x-72\right):2-84\) \(=201\)
\(\left(6.x-72\right):2\) \(=201-84\)
\(\left(6.x-72\right):2\) \(=117\)
\(6.x-72\) \(=117.2\)
\(6.x-72\) \(=234\)
\(6.x\) \(=234+72\)
\(6.x\) \(=306\)
\(x\) \(=306:6\)
\(x\) \(=51\)
mik nè
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a)(2367-x)-1017=205\)
\(\Leftrightarrow(2367-x)=205+1017\)
\(\Leftrightarrow(2367-x)=1222\)
\(\Leftrightarrow x=2367-1222\)
\(\Leftrightarrow x=1145\)
\(b)(6x-39):3\cdot28=5628\)
\(\Leftrightarrow(6x-39):3=\frac{5628}{28}\)
\(\Leftrightarrow(6x-39):3=201\)
\(\Leftrightarrow(6x-39)=201\cdot3\)
\(\Leftrightarrow(6x-39)=603\)
\(\Leftrightarrow6x=603+39\)
\(\Leftrightarrow6x=642\)
\(c)5x-x+2x=42\)
\(\Rightarrow5x-1x+2x=42\)
\(\Rightarrow6x=42\)
\(\Rightarrow x=7\)
d\()\)Tương tự câu a và b
e\()(x-2)(x-3)=0\)
Xét có hai trường hợp :
TH1 : x - 2 = 0 => x = 2
TH2 : x - 3 = 0 => x = 3
Vậy : \(\hept{\begin{cases}x=2\\x=3\end{cases}}\)
\(\Leftrightarrow x=\frac{642}{6}=107\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c) 10 + 2x = 2(32 - 1)
10 + 2x = 16
2x = 6
x = 3
d) 2x - 138 = 23.32
2x - 138 = 72
2x = 72 + 138
2x = 210
x = 210/2 = 105
a) 1032 : (x : 4) = 6
x : 4 = 1032 : 6 = 172
X = 172 x 4 = 688
b) 123 - 5(x + 4) = 38
5(x + 4) = 123 - 38 = 85
x + 4 = 85/5 = 17
x = 17 - 4 = 13
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(2x-13=2^3.3^2\)
=> \(2x-13=8.9=27\)
=> \(2x=27-13=14\)
=> \(x=7\)
b) \(231-\left(x-6\right)=1339:13=103\)
=> \(x-6=231-103=128\)
=> \(x=6+218=224\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(6-2\left(x+4\right)=-4\)
\(\Leftrightarrow6-2x-8=-4\)
\(\Leftrightarrow-2-2x=-4\)
\(\Leftrightarrow-2x=-4+2\)
\(\Leftrightarrow-2x=-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
b) tự làm.
c) \(2x-15:5=-7\)
\(\Leftrightarrow2x-7,5=-7\)
\(\Leftrightarrow2x=-7+7,5\)
\(\Leftrightarrow2x=0,5\)
\(\Leftrightarrow x=0,25\)
\(\Leftrightarrow x=\dfrac{1}{4}\)
Vậy \(x=\dfrac{1}{4}\)
d) \(231-\left(x-6\right)=1339:13\)
\(\Leftrightarrow231-x+6=103\)
\(\Leftrightarrow237-x=103\)
\(\Leftrightarrow237-x+6=103\)
\(\Leftrightarrow-x=103-237\)
\(\Leftrightarrow-x=-134\)
\(\Leftrightarrow x=134\)
e) đề j mà có 2 dấu bằng >> sai :v
f) \(28-x^3=1\)
\(\Leftrightarrow-x^3=1-28\)
\(\Leftrightarrow-x^3=-27\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
g) \(\left(x+2\right)^3=27\)
\(\Leftrightarrow\left(x+2\right)^3=3^3\)
\(\Leftrightarrow x+2=3\)
\(\Leftrightarrow x=3-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
h) \(81-\left(x-5\right)^2=56\)
\(\Leftrightarrow-\left(x-5\right)^2=56-81\)
\(\Leftrightarrow-\left(x-5\right)^2=-25\)
\(\Leftrightarrow\left(x-5\right)^2=25\)
\(\Leftrightarrow x-5=\pm5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)
Vậy \(x_1=0;x_2=10\)
j) \(x^2=9\)
\(\Leftrightarrow x=\pm3\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x_1=-3;x_2=3\)
l) tự làm.
a, 231 - ( x- 6) = 1339 : 13
231 - ( x - 6) =103
x - 6 = 231 - 103
x -6 = 128
x = 128 + 6
x = 134
b, 5 (2x - 3) = 105
2x - 3 = 105: 5
2x - 3 = 21
2x = 21 + 3
2x = 24
x = 24 : 12
x = 2
c, Dề thiếu
Đúng cho mình đã nha
a, 231 - (x- 6) = 1339 : 13
231 - (x - 6) = 103
x - 6 = 231 - 103
x - 6 = 128
x = 128 + 6
x = 134
b, 5 . (2x - 3) = 105
2x - 3 = 105: 5
2x - 3 = 21
2x = 21 + 3
2x = 24
x = 24 : 12
x = 2
c) Không có đẳng thức hay hay bất đẳng thức => không tìm x được. Bạn xem lại đề.