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a) 9x-1=32
( 32 )x-1 = 32
32x-2 = 32
⇒ 2x-2 = 2
2x = 2+2
2x = 4
x = 4 : 2
x = 2
b) 5x+2=625
5x+2= 54
⇒ x+2 = 4
x = 4-2
x = 2
c) 2x: 25= 2
2x:25 = 21
2x = 21 . 25
2x = 26
⇒ x = 6
d) 3x:27=3
3x:33 = 31
3x = 31.33
3x = 34
⇒ x = 4
a) Ta có: \(9^{x-1}=3^2\)
\(\Leftrightarrow3^{2x-2}=3^2\)
\(\Leftrightarrow2x-2=2\)
\(\Leftrightarrow2x=4\)
hay x=2
Vậy: x=2
b) Ta có: \(5^{x+2}=625\)
\(\Leftrightarrow5^{x+2}=5^4\)
\(\Leftrightarrow x+2=4\)
hay x=2
Vậy: x=2
c) Ta có: \(2^x:2^5=2\)
\(\Leftrightarrow2^{x-5}=2^1\)
\(\Leftrightarrow x-5=1\)
hay x=6
Vậy: x=6
d) Ta có: \(3^x:27=3\)
\(\Leftrightarrow3^x:3^3=3\)
\(\Leftrightarrow3^{x-3}=3^1\)
\(\Leftrightarrow x-3=1\)
hay x=4
Vậy: x=4
23 < 2n < 26
=> 3 < n < 6
=> n \(\in\){4 ; 5}
25 < 5n < 625
=> 52 < 5n < 54
=> 2 < n < 4
=> n = 3
a) \(2^3< 2^n< 2^6\)
\(\Rightarrow3< n< 6\)
\(\Rightarrow n\in\left\{4;5\right\}\)
b) \(25< 5^n< 625\)
\(\Rightarrow5^2< 5^n< 5^4\)
\(\Rightarrow2< n< 4\)
\(\Rightarrow n=3\)
a) \(3^{x-1}+3x+3^{x+1}=1053\)
\(=3^x:3+3^x+3^x.3=1053\)
\(=3^x.\dfrac{1}{3}+1+3=1053\)
\(=3^x.\dfrac{13}{5}=1053\)
\(=3^x=243\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
\(a,\text{ }2^{2n}\text{ : }2^5=32\)
\(2^{2n}\text{ : }2^5=2^5\)
\(2^{2n}=2^5\cdot2^5\)
\(2^{2n}=2^{10}\)
\(\Rightarrow\text{ }2n=10\)
\(n=10\text{ : }2\)
\(n=5\)
\(b,\text{ }7^{10}\text{ : }7^{2n}=49\)
\(7^{10}\text{ : }7^{2n}=7^2\)
\(7^{2n}=7^{10}\text{ : }7^2\)
\(7^{2n}=7^8\)
\(\Rightarrow\text{ }2n=8\)
\(n=8\text{ : }2\)
\(n=4\)