Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
9/11 x 10/13 + 9/13 x 12/11 - 7/11
= 9/13 x 10/11 + 9/13 x 12/11 - 7/11
= 9/13 x (10/11 + 12/11) - 7/11
= 9/13 x 22/11 - 7/11
= 9/13 x 2 - 7/11
= 18/13 - 7/11
= 198/143 - 91/143
= 107/143
\(\dfrac{9}{11}\times\dfrac{10}{13}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\dfrac{10}{11}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\left(\dfrac{10}{11}+\dfrac{12}{11}\right)-\dfrac{7}{11}=\dfrac{9}{13}\times2-\dfrac{7}{11}=\dfrac{18}{13}-\dfrac{7}{11}=\dfrac{107}{143}\)
\(\dfrac{1}{x}-\dfrac{y}{11}=-\dfrac{2}{11}\)
\(\dfrac{1}{x}=-\dfrac{2}{11}+\dfrac{y}{11}\)
\(\dfrac{1}{x}=\dfrac{y-2}{11}\)
\(x\left(y-2\right)=11\)
\(\Rightarrow x,\left(y-2\right)\inƯ\left(11\right)=\left\{1,-1,11,-11\right\}\)
có bảng sau :
x | 1 | -1 | 11 | -11 |
x | 1 | -1 | 11 | -11 |
y-2 | 11 | -11 | 1 | -1 |
y | 13 | -9 | 3 | 1 |
Vậy ...
\(\dfrac{1}{x}-\dfrac{y}{11}=-\dfrac{2}{11}\Rightarrow11-xy=-2x\)
\(\Leftrightarrow-2x+xy=11\Leftrightarrow x\left(-2+y\right)=11\)
\(\Rightarrow x;y-2\inƯ\left(11\right)=\left\{\pm1;\pm11\right\}\)
x | 1 | -1 | 11 | -11 |
y-2 | 11 | -11 | 1 | -1 |
y | 13 | -9 | 3 | 1 |
a) \(2\dfrac{3}{4}-x=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{11}{4}-x=\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{11}{4}-\dfrac{3}{4}=\dfrac{8}{4}=2\)
b) \(x:\dfrac{5}{6}=-\dfrac{3}{5}\)
\(\Rightarrow x=-\dfrac{3}{5}.\dfrac{5}{6}=-\dfrac{15}{30}=-\dfrac{1}{2}\)
c) \(1\dfrac{1}{3}+\dfrac{2}{3}:x=1\)
\(\Rightarrow\dfrac{2}{3}:x=1-1\dfrac{1}{3}\)
\(\Rightarrow\dfrac{2}{3}:x=-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{3}:-\dfrac{1}{3}\)
\(\Rightarrow x=-2\)
d) \(x-\dfrac{1}{9}=\dfrac{8}{3}\)
\(\Rightarrow x=\dfrac{8}{3}+\dfrac{1}{9}\)
\(\Rightarrow x=\dfrac{25}{9}\)
e) \(\dfrac{1}{2}x+650\%x-x=-6\)
\(\Rightarrow\dfrac{1}{2}x+\dfrac{13}{2}x-x=-6\)
\(\Rightarrow x\left(\dfrac{1}{2}+\dfrac{13}{2}-1\right)-6\)
\(\Rightarrow6x=-6\)
\(\Rightarrow x=\dfrac{-6}{6}=-1\)
g) \(2\left(x-\dfrac{1}{2}\right)+3\left(-1+\dfrac{x}{3}\right)=x\left(\dfrac{2}{x}-1\right)\) \(\text{Đ}K:x\ne0\)
\(\Rightarrow2x-1-3+x=2-x\)
\(\Rightarrow3x-4=2-x\)
\(\Rightarrow3x+x=2+4\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\dfrac{6}{4}=\dfrac{3}{2}\)
`2^(16).8^(10).16^11`
`=2^(16).(2^3)^{10}.(2^4)^11`
`=2^(16).2^(30).2^(44)`
`=2^(16+30+44)`
`=2^90`
`(75 : 3 + 2 . 9^2) : x = 11`
`=> (75 : 3 + 2 . 81) : x = 11`
`=> (25+ 162) : x = 11`
`=> 187 : x = 11`
`=>x=187:11`
`=>x=17`
\(\left(75:3+2.9^2\right):x=11\)
\(\left(25+2.81\right):x=11\)
\(\left(25+162\right):x=11\)
\(187:x=11\)
\(x=187:11\)
\(x=17\)
TL :
(75:3 + 2.9^2):x = 11
(25 + 162):x = 11
187:x = 11
x = 187: 11
x = 17.