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2. => 4x^3-4x = 0
=> 4x.(4x^2-1) = 0
=> x.(4x^2-1) = 0
=> x.(2x-1).(2x+1) = 0
=> x=0 hoặc 2x-1=0 hoặc 2x+1=0
=> x=0 hoặc x=1/2 hoặc x=-1/2
Vậy x thuộc {-1/2 ; 0 ; 1/2}
Tk mk nha
Lời giải:
$1,2+2,3+3,4+...+98,99+99,100=2,4x-1$
$(1+0,2)+(2+0,3)+(3+0,4)+...+(98+0,99)+(99+0,100)=2,4x-1$
$(1+2+3+...+98+99)+(0,2+0,3+0,4+...+0,99+0,100)=2,4x-1$
$=99.100:2 + (0,2+0,3+...+0,9)+(0,10+0,11+0,12+...+0,99)+0,1=2,4x-1$
$4950+0,1(2+3+...+9)+0,01(10+11+...+99)+0,1=2,4x-1$
$4950+0,1.44+0,01.4905+0,1=2,4x-1$
$5003,55=2,4x-1$
$x=\frac{100091}{48}$
( 3/5 - 2,4x) : 1 5/8 = -4
( 3/5 - 2,4x) = -4 . 13/8
3/5 - 2,4x = -13/2
2,4x = 3/5 - (-13/2)
2,4x = 6/10 - (-65/10)
2,4x = 71/10
x = 71/10 : 2,4
x = 71/10 . 10/24
x = 71/24.
Vi may bi chap choe nen minh khong dung duoc cac ki hieu toan mong ban thong cam.
Chu y: 1 5/8 chinh la mot nam phan tam do.
Ta có: \(\left(\dfrac{3}{5}-2,4x\right):1\dfrac{5}{8}=-4.\)
\(\left(\dfrac{3}{5}-\dfrac{12}{5}x\right):\dfrac{13}{8}=-4.\)
\(\left(\dfrac{3}{5}-\dfrac{12}{5}x\right)=-4.\dfrac{13}{8}.\)
\(\left(\dfrac{3}{5}-\dfrac{12}{5}x\right)=\dfrac{-13}{2}.\)
\(\dfrac{12}{5}x=\dfrac{3}{5}-\dfrac{-13}{2}.\)
\(\dfrac{12}{5}x=\dfrac{6}{10}+\dfrac{65}{10}.\)
\(\dfrac{12}{5}x=\dfrac{71}{10}.\)
\(x=\dfrac{71}{10}:\dfrac{12}{5}.\)
\(x=\dfrac{71}{10}.\dfrac{5}{12}.\)
\(x=\dfrac{355}{120}.\)
Rút gọn: \(x=\dfrac{71}{24}=2\dfrac{23}{24}.\)
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\(\left(2,4x-36\right)=-1.\frac{12}{7}\)
\(\left(2,4x-36\right)=\frac{-12}{7}\)
\(2,4x=\frac{-12}{7}+36\)
\(2,4x=\frac{240}{7}\)
\(x=\frac{240}{7}:2,4\)
\(x=\frac{100}{7}\)
\(\left(2,4x-36\right):1\frac{5}{7}=-1\)
2,4x - 36 = -1 . \(\frac{12}{7}=\) -12/7
2,4x = -12/7 + 36 = 240/7
x = 240/7 : 2,4 = 100/7
a) \(\frac{3}{x-5}=\frac{-4}{x+2}\)(ĐKXĐ: \(x\ne5;x\ne-2\))
\(\Rightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)(thỏa mãn ĐKXĐ)
b) \(2,4x-36=-\frac{7}{12}\)
\(\Leftrightarrow2,4x=\frac{425}{12}\)
\(\Leftrightarrow x=\frac{2125}{144}\)
c) \(\left(\frac{19}{5}-2x\right).\frac{4}{3}=\frac{40}{7}\)
\(\Leftrightarrow\frac{19}{5}-2x=\frac{30}{7}\)
\(\Leftrightarrow2x=-\frac{17}{35}\)
\(\Leftrightarrow x=-\frac{17}{70}\)
b) \(\left(2,4.x-36\right)\div1\frac{5}{7}=-1\)
\(\left(2,4.x-36\right)=-1.\frac{12}{7}\)
\(2,4.x-36=-\frac{12}{7}\)
\(2,4.x=-\frac{12}{7}+36\)
\(2,4.x=\frac{240}{7}\)
\(x=\frac{240}{7}\div2,4\)
\(x=\frac{100}{7}\)
Lời giải:
$60\text{%}+2,4x+x:3=2$
$0,6+2,4x+x.\frac{1}{3}=2$
$0,6+x(2,4+\frac{1}{3})=2$
$0,6+x.\frac{41}{15}=2$
$x.\frac{41}{15}=2-0,6=\frac{7}{5}$
$x=\frac{7}{5}: \frac{41}{15}=\frac{21}{41}$