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3.(x-1)-5.(-7)=(-2)3-2x
3.(x-1)-(-35)=(-8)-2x
3(x-1)+35=(-8)-2x
3x-1x+35=(-8)-2x
2x+35=(-8)-2x
tự giải tiếp nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
a)|x|=5
=>x=5 hoặc x=-5
b)|x-3|=2
=>x-3=2 hoặc x-3=-2
x=2+3 x=-2+3
x=5 x=1
c)x+|x|=2
|x|=2-x
=>x=2-x hoặc x=-(2-x)=-2+x
x+x=2 x-x=-2
2x=2 0=(-2)(loại)
x=2/2
x=1
d)20-7|x-1|=6
7|x-1|=20-6
|x-1|=14/7
|x-1|=2
=>x-1=2 hoặc x-1=-2
x=2+1 x=-2+1
x=3 x=-1
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1-1/2+1/3-1/4+...+1/199-1/200=(1+1/2+1/3+1/4+...+199+1/200)-(1+1/2+1/3+...+1/100)=1+1/2+1/3+1/4+...+1/199+1/200-1-1/2-1/3-1/4-...-1/99-1/100=(1+1/2+1/3+...+1/100)-(1+1/2+1/3+...+1/100)+(1/101+1/102+...+1/200)=0+(1/101+1/102+...+1/200)=(1/101+1/102+...+1/200)(đpcm)
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\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)
\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)
\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)
\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)
\(x\cdot\frac{1}{12}=\frac{-1}{3}\)
\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)
\(x=\frac{-1}{3}\cdot12\)
\(x=\frac{-12}{3}\)
\(x=-4\)
\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)
\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)
\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)
\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)
\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)
\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)
\(x=\frac{-14}{-5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
-x-20-(8-2x)=(-12-3)
-x-20-8+2x=-15
x-28=-15
x=13
Vậy x=13
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1+[-3]+5+[-7]+...+97+[-99]+101
=(1+5+9+...+97+101)+[(-3)+(-7)+...+(-99)]
=1326+(-1275)
=51