![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{5}{4x}-\dfrac{3}{2}=\dfrac{3}{2}+\dfrac{x}{2}\\ \Leftrightarrow5-6x=6x+2x^2\\ \Leftrightarrow2x^2+12x-5=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-6+\sqrt{46}}{2}\\x=\dfrac{-6-\sqrt{46}}{2}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,2xX-7/4=11/6
=> 2x = 11/6 + 7/4
=> 2x = 43/12
=> x = 43/24
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(13\cdot\left(7-x\right)=26\)
\(\Rightarrow7-x=\dfrac{26}{13}\)
\(\Rightarrow7-x=2\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
b) \(\left(4x-18\right):3=2\)
\(\Rightarrow4x-18=2\cdot3\)
\(\Rightarrow4x-18=6\)
\(\Rightarrow4x=6+18\)
\(\Rightarrow4x=24\)
\(\Rightarrow x=24:4\)
\(\Rightarrow x=6\)
c) \(2\cdot x+98\cdot2022=98\cdot2023\)
\(\Rightarrow2\cdot x=98\cdot2023-98\cdot2022\)
\(\Rightarrow2\cdot x=98\cdot\left(2023-2022\right)\)
\(\Rightarrow2\cdot x=98\cdot1\)
\(\Rightarrow x=\dfrac{98}{2}\)
\(\Rightarrow x=49\)
d) \(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+101\right)=?\)
Thiếu đề
a) \(13.\left(7-x\right)=26\)
\(7-x=26:13\)
\(7-x=2\)
\(x=7-2\)
\(x=5\)
b) \(\left(4x-18\right):3=2\)
\(4x-18=6\)
\(4x=6+18\)
\(4x=24\)
\(x=24:4\)
\(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(1+3+5+7+...+1995)+2x=996006
[(1995+1).998 : 2] + 2x = 996006
996004+2x=996006
=> 2x = 2
=> x=1
(1+3+5+7+...+1995)+2x=996006
[(1995+1).998 : 2] + 2x = 996006
996004+2x=996006
=> 2x = 2
=> x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2x+5}{x+1}\in N\\ \Leftrightarrow2x+5⋮x+1\\ \Rightarrow2\left(x+1\right)+3⋮x+1\\ \Rightarrow3⋮x+1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(2x-15)5=(2x-15)3
=> 2x-15=0 hoặc 2x-15=1 (vì 05=03)
=> 2x=0+15 hoặc 2x=1+15
=> 2x=15 hoặc 2x=16
=> x=15:2 hoặc x=16:2
=> x=7,5 hoặc x=8
Vậy x = 7,5 hoặc x = 8
Ta có : 5 + ( 2x - 1 ) = -6 - ( 5 + x )
=> 5 + 2x - 1 = -6 - 5 - x
=> 4 + 2x = -x - 11
=> 2x + x = -11 - 4
=> 3x = -15
=> x = ( -15 ) : 3 = -5