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Ta có: 100 < 52x – 1 < 56
=> 52 < 100 < 52x-1 < 56
=> 2 < 2x – 1 < 6
=> 2 + 1 < 2x < 6 + 1
=> 3 < 2x < 7
Vì x ∈ N nên suy ra: x ∈ {2; 3} là thỏa mãn.
Ta có 100=52.4
\(\Rightarrow5^3\le5^{2x-1}< 5^6\)
\(\Rightarrow3\le2x-1< 6\)
\(\Rightarrow4\le2x< 7\)
\(\Rightarrow2\le x< 3,5\)
Mà \(x\) là số tự nhiên
\(\Rightarrow x=2\) hoặc \(x=3\)
\(5^{2x-1}=125\cdot5^4\)
\(\Leftrightarrow2x-1=7\)
hay x=4
\(\Rightarrow5^{2x-3}=5^2\cdot3+5^2\cdot2=5^2\cdot5=5^3\\ \Rightarrow2x-3=3\\ \Rightarrow x=3\)
\(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}-50=75\)
\(\Rightarrow5^{2x-3}=125=5^3\)
\(\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)
\(5^{2x+1}.5^{x+1}=5^{17}\)
\(\Rightarrow5^{2x+1+x+1}=5^{17}\)
\(\Rightarrow5^{3x+2}=5^{17}\)
\(\Rightarrow3x+2=17\)
\(\Rightarrow3x=15\Rightarrow x=5\)
5²ˣ⁻³ - 2.5² = 5².3
5²ˣ⁻³ - 2.25 = 25.3
5²ˣ⁻³ - 50 = 75
5²ˣ⁻³ = 75 + 50
5²ˣ⁻³ = 125
5²ˣ⁻³ =5³
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3
\(5^{2x-3}-2.5^2=5^2.3\)
\(\Leftrightarrow5^{2x}:5^3-50=75\)
\(\Leftrightarrow5^{2x}:5^3=75+50\)
\(\Leftrightarrow5^{2x}:5^3=125\)
\(\Leftrightarrow5^{2x}=125.5^3\)
\(\Leftrightarrow5^{2x}=5^3.5^3\)
\(\Leftrightarrow5^{2x}=5^6\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=6:2\)
\(\Leftrightarrow x=3\)
Vậy x=3
5²ˣ⁻³ - 2.5² = 5².3
5²ˣ⁻³ - 2.25 = 25.3
5²ˣ⁻³ - 50 = 75
5²ˣ⁻³ = 75 + 50
5²ˣ⁻³ = 125
5²ˣ⁻³ = 5³
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3
\(5^{2x+1}\cdot5^{2x+2}-5^x\cdot5^{3x+2}=100\)
\(\Leftrightarrow5^{4x+3}-5^{4x+2}=100\)
\(\Leftrightarrow625^x\left(5^3-5^2\right)=100\)
\(\Leftrightarrow625^x=1\)
hay x=0
\(\Rightarrow5^{2x+1+2x+2}-5^{x+3x+2}=100\\ \Rightarrow5^{4x+3}-5^{4x+2}=100\\ \Rightarrow5^{4x+2}\left(5-1\right)=100\\ \Rightarrow5^{4x+2}=25=5^2\\ \Rightarrow4x+2=2\Rightarrow x=0\)
52x = 520 : 510
=> 52x = 510
=> 2x = 10
=> x = 5