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a/ x + 2x + 3x = 36
=> 6x = 36
=> x = 6
Vậy ..
b/ 7x - 2x - x = 24
=> 4x = 24
=> x = 6
Vậy ...
c/ (x : 5) - 10 = 5
=> x : 5 = 15
=> x = 75
Vậy ...
d/ 7. (x+3) = 49
=> x + 3 = 7
=> x = 4
Vậy ....
e/ (x - 5) . 4 = 32
=> x - 5 = 8
=> x = 13
Vậy. ..
g/ 7x - 3 = 25
=> 7x = 28
=> x = 4
Vậy ...
h/ 17 - (x :3) = 10
=> x : 3 = 17 - 10
=>x : 3 = 7
=> x = 21
Vậy ..
a) x + 2x + 3x = 36
=> 6x = 36
=> x = 6
b)7x - 2x - x = 24
=> 4x = 24
=> x = 6
c) (x : 5 ) - 10 = 5
=> x : 5 = 15
=> x = 3
d) 7 . ( x + 3 ) = 49
=> x + 3 = 7
=> x = 4
e) ( x - 5 ) . 4 =32
=> x - 5 = 8
=> x = 3
g) 7x - 3 = 25
=> 7x = 28
=> x = 4
h) 17 - ( x : 3 ) = 10
=> x : 3 = 7
=> x = 21
-3/8; 6/-24; -7/49
=-3/8; -1/4; -1/7
=-21/56; -14/56; -8/36
cko xin =)
a: \(x-\dfrac{10}{3}=\dfrac{7}{15}\cdot\dfrac{3}{5}\)
=>\(x-\dfrac{10}{3}=\dfrac{21}{75}=\dfrac{7}{25}\)
=>\(x=\dfrac{7}{25}+\dfrac{10}{3}=\dfrac{21+250}{75}=\dfrac{271}{75}\)
b: \(x+\dfrac{3}{22}=\dfrac{27}{121}\cdot\dfrac{9}{11}\)
=>\(x+\dfrac{3}{22}=\dfrac{243}{1331}\)
=>\(x=\dfrac{243}{1331}-\dfrac{3}{22}=\dfrac{123}{2662}\)
c: \(\dfrac{8}{23}\cdot\dfrac{46}{24}-x=\dfrac{1}{3}\)
=>\(\dfrac{8}{24}\cdot\dfrac{46}{23}-x=\dfrac{1}{3}\)
=>\(\dfrac{2}{3}-x=\dfrac{1}{3}\)
=>\(x=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
d: \(1-x=\dfrac{49}{65}\cdot\dfrac{5}{7}\)
=>\(1-x=\dfrac{49}{7}\cdot\dfrac{5}{65}=\dfrac{7}{13}\)
=>\(x=1-\dfrac{7}{13}=\dfrac{6}{13}\)
a) \(\frac{x}{2}-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)
\(\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)
\(\frac{x}{2}=\frac{117}{35}\)
\(x=\frac{117}{35}\times2\)
\(x=\frac{234}{35}\)
b) \(\frac{y}{5}+\frac{9}{2}=\frac{6}{7}.\frac{36}{49}\)
\(\frac{y}{5}+\frac{9}{2}=\frac{216}{343}\)
\(\frac{y}{5}=\frac{216}{343}-\frac{9}{2}\)
\(\frac{y}{5}=\frac{-2655}{686}\)
\(y=\frac{-2655}{686}.5\)
\(y=\frac{-13275}{686}\)
ra kết quả to quá bn ạ! Bn xem lại giúp mk nha!
đáp án =0
5/24-84-49/3
=-2011/24-49/3
=-801/8