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\(C=-\left[\dfrac{1}{3}\cdot\dfrac{\left(3+1\right)\cdot3}{2}+\dfrac{1}{4}\cdot\dfrac{\left(4+1\right)\cdot4}{2}+...+\dfrac{1}{50}\cdot\dfrac{\left(50+1\right)\cdot50}{2}\right]\\ C=-\left(\dfrac{1}{3}\cdot\dfrac{4\cdot3}{2}+\dfrac{1}{4}\cdot\dfrac{5\cdot4}{2}+...+\dfrac{1}{50}\cdot\dfrac{51\cdot50}{2}\right)\\ C=-\left(2+\dfrac{5}{2}+...+\dfrac{51}{2}\right)\\ C=-\dfrac{4+5+...+51}{2}=-\dfrac{\dfrac{\left(51+4\right)\left(51-4+1\right)}{2}}{2}=-\dfrac{55\cdot48}{4}=-660\)
a: =>x-3/4=1/6-1/2=1/6-3/6=-2/6=-1/3
=>x=-1/3+3/4=-4/12+9/12=5/12
b: =>x(1/2-5/6)=7/2
=>-1/3x=7/2
hay x=-21/2
c: (4-x)(3x+5)=0
=>4-x=0 hoặc 3x+5=0
=>x=4 hoặc x=-5/3
d: x/16=50/32
=>x/16=25/16
hay x=25
e: =>2x-3=-1/4-3/2=-1/4-6/4=-7/4
=>2x=-7/4+3=5/4
hay x=5/8
\(\left(2018-\frac{2}{135}+\frac{1}{50}\right)-\left(1-\frac{7}{135}+\frac{4}{50}\right)-\left(5+\frac{5}{135}+\frac{3}{50}\right)\)
\(=2018-\frac{2}{135}+\frac{1}{50}-1+\frac{7}{135}-\frac{4}{50}-5-\frac{5}{135}-\frac{3}{50}\)
\(=2012-\frac{6}{50}\)
\(=\left(\dfrac{18}{5}-\dfrac{2}{5}-2\right)\cdot\dfrac{-5}{3}+3\cdot\left(\dfrac{5}{2}\cdot2\right)\)
\(=\dfrac{5}{3}\left(-\dfrac{6}{5}+1\right)=\dfrac{5}{3}\cdot\dfrac{-1}{5}=\dfrac{-1}{3}\)
\(\left(2017-\dfrac{5}{181}+\dfrac{1}{50}\right)-\left(4+\dfrac{3}{181}-\dfrac{2}{50}\right)+\left(1-\dfrac{8}{181}+\dfrac{3}{50}\right)\)
\(=2017-\dfrac{5}{181}+\dfrac{1}{50}-4-\dfrac{3}{181}+\dfrac{2}{50}+1-\dfrac{8}{181}+\dfrac{3}{50}\)
\(=2014+\dfrac{143}{4525}\)
\(=\dfrac{9113493}{4525}\)
\(50-\left[\left(50-2^3\cdot5\right)\div2+3\right]=50-\left[10\left(5-2^2\right)\div2+3\right]=50-\left(5\cdot1+3\right)=50-8=42\)
=37 nha bn