Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu 1:
\(\frac{1}{3}+\frac{3}{35}<\frac{x}{210}<\frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{44}{105}<\frac{x}{210}<\frac{158}{105}\)
\(\Rightarrow\frac{88}{210}<\frac{x}{210}<\frac{316}{210}\)
\(\Rightarrow x\in\left\{89;90;91;92;...;310;311;312;313;314;315\right\}\)
Câu 3:
\(\frac{5}{3}\)\(+\frac{-14}{3}\)\(<\)\(x\)\(<\)\(\frac{8}{5}+\frac{18}{10}\)
\(\Rightarrow\)\(-9\)\(<\)\(x\)\(<\)\(3,4\)
Mà \(x\in Z\)
\(\Rightarrow x\in\left\{-8;-7;-6;-5;...;1;2;3\right\}\)
\(\frac{5.\left(2^2.3^2\right)^9\left(2^2\right)^6-2.\left(2^2.3\right)14.3^{ }^4}{22}\)
a: \(\dfrac{5}{24}-\dfrac{6}{21}=\dfrac{35}{168}-\dfrac{48}{168}=\dfrac{-13}{168}\)
b: \(-\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{5}{18}=\dfrac{-9}{36}+\dfrac{24}{36}+\dfrac{10}{36}=\dfrac{5}{36}\)
c: \(\dfrac{2}{3}+\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{8}{12}+\dfrac{9}{12}+\dfrac{6}{12}=\dfrac{23}{12}\)
d: \(=\dfrac{3}{4}-\dfrac{2}{5}+\dfrac{1}{3}=\dfrac{45}{60}-\dfrac{24}{60}+\dfrac{20}{60}=\dfrac{41}{60}\)
a) \(\frac{7}{11}-\left(\frac{3}{5}+\frac{7}{11}\right)=-\frac{3}{5}\)
b) \(\left(\frac{11}{22}+\frac{5}{11}\right)-\frac{19}{22}=\frac{1}{11}\)
c) \(\frac{2}{9}.\frac{4}{5}+\frac{2}{9}.\frac{14}{5}=\frac{4}{5}\)
d) \(-\frac{3}{2}.\frac{7}{10}-\frac{3}{2}.\frac{1}{10}=-\frac{6}{5}\)
e) \(\left(0,75-1+\frac{1}{4}\right):\left(\frac{1515}{1616}+\frac{1616}{1717}\right)=0\)
a, Ta thấy với a,b >0 thì \(\frac{a}{b}<\frac{a+n}{b+n}\), với a,b<0 thì \(\frac{a}{b}>\frac{a+\left(-n\right)}{b+\left(-n\right)}\) \(\left(n\in Z;\right)n>0\)
Vậy ta sắp xếp như sau:
\(-\frac{8}{9};-\frac{6}{7};-\frac{4}{5};-\frac{1}{2};\frac{2}{3};\frac{3}{4};\frac{5}{6};\frac{7}{8};\frac{9}{10}\)
b, Có:
\(\frac{0}{23}=0\)
\(-\frac{14}{5}<-1<\frac{-15}{19}<-\frac{15+\left(-2\right)}{19+\left(-2\right)}=-\frac{13}{17}\)
\(\frac{5}{2}>\frac{4}{2}=2>\frac{11}{7}=\frac{99}{63}>\frac{13}{9}=\frac{91}{63}\)
Vậy ta sắp xếp như sau:
\(-\frac{14}{5};-\frac{15}{19};-\frac{13}{17};0;\frac{13}{9};\frac{11}{7};\frac{5}{2}\)
a) \(=\frac{3}{17}-\frac{2}{345}+\frac{5}{12}+\frac{2}{345}-\frac{3}{17}+\frac{1}{12}\)
\(=\left(\frac{3}{17}-\frac{3}{17}\right)+\left(\frac{2}{345}-\frac{2}{345}\right)+\left(\frac{5}{12}+\frac{1}{12}\right)\)
\(=\frac{6}{12}=\frac{1}{2}\)
b) \(=-\frac{49}{25}-\frac{5}{36}+\frac{4}{123}+\frac{49}{25}-\frac{4}{123}-\frac{1}{36}\)
\(=\left(-\frac{49}{25}+\frac{49}{25}\right)+\left(\frac{4}{123}-\frac{4}{123}\right)-\left(\frac{5}{36}+\frac{1}{36}\right)\)
\(=-\frac{6}{36}=-\frac{1}{6}\)
\(-\frac{12}{5}:\frac{7}{11}-\frac{23}{5}:\frac{7}{11}-\frac{5}{11}\)
\(=-\frac{12}{5}.\frac{11}{7}-\frac{23}{5}.\frac{11}{7}-\frac{5}{11}\)
\(=\left(-\frac{12}{5}-\frac{23}{5}\right).\frac{11}{7}+\frac{5}{11}\)
\(=-7.\frac{11}{7}-\frac{5}{11}\)
\(=-\frac{16}{11}\)
\(\frac{-12}{35}:\frac{7}{11}-\frac{23}{5}:\frac{7}{11}-\frac{5}{11}\)
\(=\frac{-12}{35}.\frac{11}{7}-\frac{23}{5}.\frac{11}{7}-\frac{5}{11}\)
\(=\frac{-132}{245}-\frac{253}{35}-\frac{5}{11}\)
\(=\frac{-132}{245}-\frac{1771}{245}-\frac{5}{11}\)
\(=\frac{-1903}{245}-\frac{5}{11}\)
\(=\frac{-22158}{2695}\)
5 / 14 + 18 / 35 + ( 5 / 4 - 5 / 4 ) : ( 5/12)^2
= 61 / 70 + 0 : ( 5 / 12)^2
= 61 / 70 + 0
= 61 / 70