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b) 4x2 - 25 + (2x + 5)2
= (2x + 5)(2x - 5) + (2x + 5)2
= (2x + 5)(2x - 5 + 2x + 5)
= 4x(2x + 5)
phân tích đa thức thành nhân tử
a, 4x2-25-(2x-5) (2x+7)
b, x3 +27 +(x +3) (x-9)
c, 4x2y2 -(x2 + y2- z2)
\(a,4x^2-25-\left(2x-5\right)\left(2x+7\right)\)
\(=\left(2x-5\right)\left(2x+5\right)-\left(2x-5\right)\left(2x+7\right)\)
\(=\left(2x-5\right)\left(2x+5-2x-7\right)\)
\(=-2\left(2x-5\right)\)
\(b,x^3+27+\left(x+3\right)\left(x-9\right)\)
\(=\left(x+3\right)\left(x^2-3x+9\right)+\left(x+3\right)\left(x-9\right)\)
\(=\left(x+3\right)\left(x^2-3x+9+x-9\right)\)
\(=\left(x+3\right)\left(x^2-2x\right)\)
\(=x\left(x+3\right)\left(x-2\right)\)
=.= hok tốt!!
\(=\left(2x-5\right)\left(2x+5\right)-\left(2x-5\right)\left(2x+7\right)\)
\(=\left(2x-5\right)\left(2x+5-2x-7\right)\)
\(=-2\left(2x-5\right)\)
= ( 2x - 5 )(2x + 5) - ( 2x- 5 )(2x + 7 )
= (2x - 5 ) [ 2x+ 5 - ( 2x+ 7 ) ]
= ( 2x- 5 ) ( 2x + 5 - 2x - 7 )
= - 2( 2x- 5 )
b) 4x2 – 9 + (2x + 3)2
= (4x2 - 9) + (2x + 3)2
= (2x + 3)(2x - 3) + (2x + 3)2
= (2x + 3)(2x - 3 + 2x + 3)
= 4x(2x + 3)
a) x3 + 4x2 – 2x – 8
= (x3 + 4x2) - (2x + 8)
= x2(x + 4) - 2(x + 4)
= (x + 4)(x2 - 2)
= (x + 4)(x + √2)(x - √2)
1) \(x\left(4x+1\right)\)
2) \(3\left(x-3y\right)\)
3) \(\left(2x+1\right)\left(2x+1+2\right)=\left(2x+1\right)\left(2x+3\right)\)
\(\left(2x-y\right)\left(4x^2-4xy+y^2\right)-8x^2\left(x-y\right)\)
\(=\left(2x-y\right)^3-8x^2\left(x-y\right)\)
\(=8x^3-12x^2y+6xy^2-y^3-8x^3+8x^2y\)
\(=-4x^2y-6xy^2-y^3\)
\(=-y\left(4x^2+6xy+y^2\right)\)
\(4x^2-25+\left(2x+7\right).\left(5-2x\right)\)
\(=\left(2x\right)^2-5^2+\left(2x+7\right).\left(5-2x\right)\)
\(=\left(2x-5\right).\left(2x+5\right)-\left(2x+7\right).\left(2x-5\right)\)
\(=\left(2x-5\right).\left(2x+5-2x-7\right)\)
\(=\left(2x-5\right).\left(-2\right)\)