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Bài 2
a: =>x=-23-7=-30
b: =>75:x=15
hay x=5
c: =>2(x+4)=80
=>x+4=40
hay x=36
d: \(\Leftrightarrow2^x\cdot11=88\)
hay x=3
Bài 3:
Có thể chia được nhiều nhất 12 tổ vì UCLN(180;132)=12
Khi đó, mỗi tổ có 15 nam và 11 nữ
a) \(-39-\left(15+x\right)=18\)
\(-39-15-x=18\)
\(-54-x=18\)
\(x=-54-18\)
\(x=-72\)
vậy \(x=-72\)
b) \(31-\left(13+x\right)=18.\left(-4\right)\)
\(31-13-x=-72\)
\(18-x=-72\)
\(x=18+72\)
\(x=90\)
vậy \(x=90\)
c) \(58-\left(47+3x\right)=-18-2x\)
\(58-47-3x+2x=-18\)
\(11-x=-18\)
\(x=11+18\)
\(x=29\)
vậy \(x=29\)
d) \(37-\left(115+x\right)=188\)
\(37-115-x=188\)
\(-78-x=188\)
\(x=-78-188\)
\(x=-266\)
vậy \(x=-266\)
a)
\(-39-\left(15+x\right)=18\)
\(\Rightarrow15+x=-39-18\)
\(\Rightarrow15+x=-57\)
\(\Rightarrow x=-57-15\)
\(\Rightarrow x=-72\)
Vậy \(x=-72\)
b)
\(31-\left(13+x\right)=18.\left(-4\right)\)
\(\Rightarrow31-\left(13+x\right)=-72\)
\(\Rightarrow13+x=31-\left(-72\right)\)
\(\Rightarrow13+x=103\)
\(\Rightarrow x=103-13\)
\(\Rightarrow x=90\)
Vậy \(x=90\)
Trả lời :
1, |-165| + |70| - 400 = 165 + 70 - 400 = 235 - 400 = -165
2, (-3) + 4 + 18 = 1 + 18 = 19
3, ( - 10 ) + ( -9 ) + 6 = -19 + 6 = -13
4, 5 - 10 + 4 = -1
5, (-15) + |-45| + 15 = [ ( - 15 ) + 15 ] + |-45| = 0 + 45 = 45
6, 13 + |-128| - 2 = 13 + 128 - 2 = 139
7, ( - 115 ) - 18 + 115 = [ (-115) + 115 ] - 18 = 0 - 18 = -18
8, 26 + 59 + 145 - 59 - 26 = ( 26 - 26 ) + (59 - 59 ) + 145 = 0 + 0 = 145 = 145
Have a nice dayy !!
#N
\(\left(x+42\right)^2\cdot115=4\cdot115\)
=>\(\left(x+42\right)^2=4\)
=>\(\left[{}\begin{matrix}x+42=2\\x+42=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-40\\x=-44\end{matrix}\right.\)
\(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125-\left(-75\right)+32-80\)
\(=125+75+32-80\)
\(=200+32-80\)
\(=232-80\)
\(=152\)
\(-63+415-37-115\)
\(=352-57-115\)
\(=315-115\)
\(=200\)
\(13.\left(-2\right)^2+37.4+4.\left(-150\right)\)
\(=13.2^2+37.4+4.-150\)
\(=13.4+37.4+4.-150\)
\(=4.\left(13+37+-150\right)\)
\(=4.-100\)
\(=-400\)
\(-15.x+4=79\)
\(\Leftrightarrow-15.x=79-4\)
\(\Leftrightarrow-15.x=75\)
\(\Leftrightarrow x=75:-15\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
\(15-\left(2+x\right)=23\)
\(\Leftrightarrow2+x=15-23\)
\(\Leftrightarrow2+x=-8\)
\(\Leftrightarrow x=-8-2\)
\(\Leftrightarrow x=-10\)
Vậy \(x=-10\)
\(\left(x+2\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-1^2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow x=\pm1\)
Vậy \(x\in\left\{\pm1\right\}\)
\(56:\left|x-4\right|=7\)
\(\Leftrightarrow\left|x-4\right|=56:7\)
\(\Leftrightarrow\left|x-4\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=8\\x-4=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8+4\\x=-8+4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=12\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{12;-4\right\}\)
\(4^x-23=115\)
\(\Rightarrow4^x=115+13\)
\(\Rightarrow4^x=128\)
\(\Rightarrow\left(2^2\right)^x=2^7\)
\(\Rightarrow2^{2x}=2^7\)
\(\Rightarrow2x=7\)
\(\Rightarrow x=\dfrac{7}{2}\)