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\(a,\dfrac{3}{5}+\dfrac{1}{5}.\dfrac{-17}{9}=\dfrac{3}{5}-\dfrac{17}{45}=\dfrac{27}{45}-\dfrac{17}{45}=\dfrac{10}{45}=\dfrac{2}{9}\\ b,\left(-\dfrac{4}{15}-\dfrac{18}{19}\right)-\left(\dfrac{20}{19}+\dfrac{11}{15}\right)=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=\left(-\dfrac{4}{15}-\dfrac{11}{15}\right)-\left(\dfrac{18}{19}+\dfrac{20}{19}\right)=-1-2=-3\)
\(a,=\dfrac{3}{5}+\left(-\dfrac{17}{45}\right)=\dfrac{2}{9}\)
\(b,=-\dfrac{4}{15}-\dfrac{18}{19}-\dfrac{20}{19}-\dfrac{11}{15}=-3\)
\(\dfrac{8^2.4^5}{2^{20}}\) = \(\dfrac{\left(2^3\right)^2\left(2^2\right)^5}{2^{20}}\) = \(\dfrac{2^6.2^{10}}{2^{20}}\) = \(\dfrac{2^{16}}{2^{20}}\) = \(\dfrac{1}{2^4}\) = \(\dfrac{1}{16}\)
a) Ta có bảng tần số
x | 17 | 18 | 19 | 20 | 21 |
n | 1 | 3 | 5 | 5 | 1 |
b) \(\frac{\text{17x1+18*3+19*5+20*5+21*1}}{15}\)
\(\approx\)19,13
#học tốt#
=-4/15 - 18/19-20/19-11/15
= (-4/15-11/15) - (18/19+20/19)
= -1 - 2
= - 3
\(\left(\frac{-4}{15}-\frac{18}{19}\right)-\left(\frac{20}{19}+\frac{11}{15}\right)=\frac{-4}{15}-\frac{18}{19}-\frac{20}{19}-\frac{11}{15}\)
\(=\left(\frac{-4}{15}-\frac{11}{15}\right)-\left(\frac{18}{19}+\frac{20}{19}\right)=\frac{-15}{15}-\frac{38}{19}=-1-2=-3\)