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a ) \(2x:6=5:3\)
\(\Leftrightarrow\frac{2x}{6}=\frac{5}{3}\)
\(\Leftrightarrow2x=5.6:3\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\)
Các câu còn lại tương tự .
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3x - 12/5 = -0,6
3x = -0,6 + 12/5
3x = -0,6 + 2,4
3x = 1,8
x = 1,8 : 3
x = 0,6
`# \text {04th5.}`
$3x - \dfrac{12}{5} = -0,6$
$\Rightarrow 3x = -0,6 + \dfrac{12}{5}$
$\Rightarrow 3x = \dfrac{9}{5}$
$\Rightarrow x = \dfrac{9}{5} \div 3$
$\Rightarrow x = \dfrac{3}{5}$
Vậy, $x = \dfrac{3}{5}.$
![](https://rs.olm.vn/images/avt/0.png?1311)
3\(x\) - \(\dfrac{12}{5}\) = -0,6
3\(x\) - 2,4 = -0,6
3\(x\) = 0,6 + 2,4
3\(x\) = 3
\(x\) = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
`@``dn10`
`a,`
`P(x)=-2x^5-3x^4+2x^5+2x-0,6`
`P(x)=(-2x^5+2x^5)-3x^4+2x-0,6`
`P(x)=-3x^4+2x-0,6`
`b,`
Thay `x=1` vào đa thức `B(x)`
`B(1)=-4*1^3+6*1-4=-4*1+6-4=-4+6-4=2-4=-2`
a: =-2x^5+2x^5+3x^4+2x-0,6
=3x^4+2x-0,6
b: B(1)=-4+6-4=-8+6=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=\left(-\dfrac{6}{5}:\left(\dfrac{8}{5}\cdot\dfrac{5}{4}\right):\dfrac{16}{25}-\dfrac{1}{25}\right)+\left[\left(1.08-0.08\right)\cdot\dfrac{7}{4}:\left(5+\dfrac{5}{9}-\dfrac{9}{4}\right)\cdot\dfrac{36}{17}\right]+0.3\cdot\dfrac{5}{2}\)
\(=\left(-\dfrac{6}{5}\cdot\dfrac{1}{2}\cdot\dfrac{16}{25}-\dfrac{1}{25}\right)+\left[\dfrac{7}{4}:\cdot\dfrac{36}{119}\cdot\dfrac{36}{17}\right]+0.75\)
\(=-\dfrac{53}{125}+\dfrac{324}{289}+0.75\simeq1,45\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=\frac{-1,2:\left(1\frac{3}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{5}\right):\frac{4}{7}}{\left(5\frac{5}{9}-\frac{9}{4}\right).\frac{36}{17}}+0,6.0,5:\frac{2}{5}\)
\(M=\frac{-1,2:\left(\frac{8}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{0,68:\frac{4}{7}}{\left(\frac{50}{9}-\frac{9}{4}\right).\frac{36}{17}}+0,6.0,5.\frac{5}{2}\)
\(M=\frac{-1.2:2}{0,6}+\frac{1,19}{\frac{119}{36}.\frac{36}{17}}+0.6.0,5.\frac{5}{2}\)
\(M=\frac{-0,6}{0,6}+\frac{1,19}{7}+0,75\)
\(M=-1+0,17+0,75=-0,08=\frac{-2}{25}\)
cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt :>
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-0,64\right):\frac{3}{5}=0,6\)
\(\Leftrightarrow\left(3x-0,64\right).\frac{5}{3}=0,6\)
\(\Leftrightarrow3x-0,64=0,36\)
\(\Leftrightarrow3x=1\)
\(\Leftrightarrow x=\frac{1}{3}\)
Vậy ................
\(\left(3x-0,64\right):\frac{3}{5}=0,6\)
\(\left(3x-\frac{16}{25}\right)=0,6.\frac{3}{5}\)
\(3x-\frac{16}{25}=\frac{9}{25}\)
\(3x=1\)
\(x=\frac{1}{3}\)