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a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
=16x2x(-39) + 16x(-22)
= 16 x (-78) + 16 x (-22)
= 16 x ( -78 + (-22)
= 16 x (-100)
= -1600
\(17\times2\times\left(-84\right)+17\times\left(-22\right)\)
\(17\times\left(-168\right)+17\times\left(-22\right)\)
\(17\times\left(-168+\left(-22\right)\right)\)
\(17\times\left(-190\right)\)
-3230
\(=60-\dfrac{\left[36+64\right]}{25}\)
\(=60-4=56\)
a) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
b) \(15-\left(3+2x\right)=2^2\)
\(\Rightarrow3+2x=15-4\)
\(\Rightarrow3+2x=11\)
\(\Rightarrow2x=11-3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=\dfrac{8}{2}\)
\(\Rightarrow x=4\)
c) \(-11-\left(19-x\right)=50\)
\(\Rightarrow19-x=-11-50\)
\(\Rightarrow19-x=-61\)
\(\Rightarrow x=61+19\)
\(\Rightarrow x=80\)
d) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
e) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=52-17\)
\(\Rightarrow79-x-43=35\)
\(\Rightarrow36-x=35\)
\(\Rightarrow x=1\)
f) \(\left(7+x\right)-\left(21-13\right)=32\)
\(\Rightarrow7+x-8=32\)
\(\Rightarrow x-1=32\)
\(\Rightarrow x=32+1\)
\(\Rightarrow x=33\)
g) \(-x+20=-15+8+13\)
\(\Rightarrow-x+20=6\)
\(\Rightarrow x=20-6\)
\(\Rightarrow x=14\)
h) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow x-13+142+18=55\)
\(\Rightarrow x+147=55\)
\(\Rightarrow x=55-147\)
\(\Rightarrow x=-92\)
Vì (x-5)22\(\ge\)0
\(\left(y+7\right)^{12}\ge0\)
Mà \(\left(x-5\right)^{22}+\left(y+7\right)^{12}=0\)
Nên \(\hept{\begin{cases}\left(x-5\right)^{22}=0\\\left(y+7\right)^{12}=0\end{cases}}\Rightarrow\hept{\begin{cases}x-5=0\\y+7=0\end{cases}}\Rightarrow\hept{\begin{cases}x=5\\y=-7\end{cases}}\)
Vì (x - 5)22 ≥ 0 ; (y + 7)12 ≥ 0
=> (x - 5)22 + (y + 7)12 ≥ 0
Dấu "=" xảy ra khi (x - 5)22 = 0 ; (y + 7)12 = 0
=> x = 5 ; y = - 7
Vậy x = 5 ; y = - 7
\(x\) - (10 - \(x\)) = \(x\) - 22
\(x\) - 10 + \(x\) = \(x\) - 22
2\(x\) - 10 = \(x\) - 22
2\(x\) - \(x\) = -22 + 10
\(x\) = - 12
\(\dfrac{2^2}{1\times3}\times\dfrac{3^2}{2.4}\times\dfrac{4^2}{3.5}\times\dfrac{5^2}{4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.3.2.4.3.5.4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.2.3.3.4.4.5.2.3}=\dfrac{2^2.3^2.4^2.5^2}{3^3.2^2.4^2.5.1}=\dfrac{5}{3.1}=\dfrac{5}{3}\)
\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot\dfrac{5^2}{4.6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot2\cdot4^2\cdot4^2\cdot5\cdot6}\\ =\dfrac{2\cdot5}{6}=\dfrac{5}{3}\)
a. = 5 x 53 x 54 = 5(1+3+4) = 58
b. = 10 x 102 x 103 = 10(1+2+3) = 106
Làm đc từng này thôi nha
Xl bạn
\(a;5\times125\times625=5\times5^3\times5^4=5^8\)
\(b;10\times100\times1000=10\times10^2\times10^3=10^6\)
\(d;8^4\times16^5\times32=2^{12}\times2^{20}\times2^5=2^{37}\)
\(5^{40}\times81^{10}=5^{40}\times3^{40}=15^{40}\)
32 . ( x+5 ) = 52 + 5 + 52
9 . ( x + 5 ) = 25 + 5 + 25
9 . ( x + 5 ) = 55
( x + 5 ) = 55 : 9
x + 5 = \(\dfrac{55}{9}\)
x = \(\dfrac{55}{9}-5\)
x = \(\dfrac{10}{9}\)
* Dấu "." là dấu nhân