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Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)
viết rõ lại cái đề giùm tui tui mới làm được
` a) 4 8/23 + 5 7/8 - 9 8/23 `
`= 100/23 + 47/8 - 215/23 `
`= ( 100/23 - 215/23) + 47/8 `
`= -115/23 + 47/8 `
`= -5 + 47/8 `
`= -5/1 + 47/8 `
`= -40/8 + 47/8 `
`=7/8`
`b) 8 2/7 - ( 3 4/9 + 4 2/7 ) `
`= 58/7 - 31/9 - 30/7 `
`= (58/7 - 30/7 ) - 31/9 `
`= 28/7 - 31/9 `
` = 252/63 - 217/63 `
`= 35/63`
`= 5/9`
`@ animephamdanhv.`
a)\(4\dfrac{8}{23}+5\dfrac{7}{8}-9\dfrac{8}{23}=\dfrac{100}{23}+\dfrac{47}{8}-\dfrac{215}{23}=\dfrac{100}{23}-\dfrac{215}{23}+\dfrac{47}{8}=-\dfrac{115}{23}+\dfrac{47}{8}=-5+\dfrac{47}{8}=\dfrac{7}{8}\)
b) \(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}=\dfrac{58}{7}-\dfrac{30}{7}-\dfrac{31}{9}=4-\dfrac{31}{9}=\dfrac{5}{9}\)
Ta có: \(\dfrac{5}{9}+\dfrac{13}{7}+\dfrac{15}{3}+\dfrac{8}{7}+\dfrac{4}{9}+\dfrac{11}{13}\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{13}{7}+\dfrac{8}{7}\right)+5\dfrac{11}{13}\)
\(=9+\dfrac{11}{13}\)
\(=\dfrac{128}{13}\)
\(C=\dfrac{3}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{3}{7}-\dfrac{3}{7}\)
\(=\dfrac{3}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{3}{7}-\dfrac{3}{7}\times1\)
\(=\dfrac{3}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}-1\right)\)
\(=\dfrac{3}{7}\times0=0\)
\(D=8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)
\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)
\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)
\(=\left(\dfrac{58}{7}-\dfrac{30}{7}\right)-\dfrac{31}{9}\)
\(=4-\dfrac{31}{9}=\dfrac{36}{9}-\dfrac{31}{9}\)
\(=\dfrac{5}{9}\)
\(\dfrac{3}{8}+\dfrac{1}{4}=\dfrac{3}{8}+\dfrac{2}{8}=\dfrac{5}{8}\)
=> Chọn A
30 đơn vị, 5 phần mười, 8 phần trăm, 6 phần nghìn: 30,586
650 đơn vị, 9 phần trăm, 4 phần nghìn, 2 phần chục nghìn: 650,0942
7 đơn vị, 25 phần trăm, 9 phần nghìn 2 phần chục nghìn: 7,2592
15 đơn vị, 2 phần mười, 7 phần trăm, 3 phần triệu: 15,270003
a: 5/7+5/4
=20/28+35/28=55/28
b: 3/2-4/6
=9/6-4/6=5/6
c: 5x3/4=15/4
d: 4/6:8=2/3x1/8=2/24=1/12
3/8+9/5=87/40
2-5/6=7/6
5/7-4/9=17/63
7/8+3/4=13/8
\(\frac{3}{8}+\frac{9}{5}=\frac{15}{40}+\frac{72}{40}=\frac{87}{40}\)
\(\frac{5}{7}-\frac{4}{9}=\frac{45}{63}-\frac{28}{63}=\frac{17}{63}\)
\(2-\frac{5}{6}=\frac{12}{6}-\frac{5}{6}=\frac{7}{6}\)
\(\frac{7}{8}+\frac{3}{4}=\frac{7}{8}+\frac{6}{8}=\frac{13}{8}\)