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a) \(2^x+2^{x+3}=144\)
\(2^x\left(1+2^3\right)=144\)
\(2^x.9=144\)
\(2^x=144:9=16\)
=> \(2^x=2^4\Rightarrow x=4\)
b) \(2^{x-1}+5.2^{x-2}=224\)
\(2^{x-2}\left(2+5\right)=224\)
\(2^{x-2}.7=224\Rightarrow2^{x-2}=32\Rightarrow2^{x-2}=2^5\)
=> x - 2 = 5 => x = 7
a)
\(2^{x+3}+5\cdot2^{x+2}=224\)
\(2^x\cdot2^3+5\cdot2^x\cdot2^2=224\)
\(2^x\cdot8+2^x\cdot20=224\)
\(2^x\cdot\left(20+8\right)=224\)
\(2^x\cdot28=224\)
\(2^x=8\)
\(x=3\)
2x+3+5*2x+2 = 224
VT=7*2x+2
pt trở thành 7*2x+2=224
<=>7*2x+2=25*7
<=>2x+2=25
<=>x+2=5
<=>x=3
a) \(2^{x-1}+5\cdot2^{x-2}=224\)
\(2^x:2+5\cdot2^x:4=224\)
\(2^x\left(\frac{1}{2}+\frac{5}{4}\right)=224\)
\(2^x=128\)
\(x=7\)
b) \(5^{x-2017}+5^{x-2015}=650\)
\(5^{x-2015}\left(\frac{1}{25}+1\right)=650\)
\(5^{x-2015}=625\)
\(x=2019\)
c) \(2^x-2^y=256\left(x>y\right)\)
(ko biết)
a: \(2^7+\left(x-3^7\right)=5^7-4^7\)
=>\(128+x-2187=78125-16384\)
=>\(x-2059=61741\)
=>\(x=61741+2059=63800\)
c: \(7^2-\left(x+15\right)=5\cdot2^2\)
=>49-(x+15)=5*4=20
=>x+15=29
=>x=14
d: 7^3-7(13-x)=14
=>343-7(13-x)=14
=>7(13-x)=343-14=329
=>13-x=47
=>x=13-47=-34
a: \(\Leftrightarrow3^x\left(1+3^2\right)=2430\)
\(\Leftrightarrow3^x=243\)
hay x=5
b: \(\Leftrightarrow2^x\left(2^8-1\right)=224\)
=>2x=32
hay x=5
2x+3 + 5.2x+2 = 224
2x.23 + 5.2x.22 = 224
2x.(8 + 5.4) = 224
=> 2x . 28 = 224
=> 2x = 8 = 23
=> x = 3
2x+3 + 5.2x+2 =224
<=> 2x+2 . 2 + 5 . 2x+2 = 224
<=> 2 x+2 . (2+5) = 224
<=> 2x+2 . 7 = 224
<=> 2 x+2 = 32
<=> 2x+2 = 2 5
<=> x + 2 = 5
<=> x= 5 - 2
<=> x = 3
Vậy :X =3