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\(A.3^x+37=188\)
\(\Rightarrow3^x=188-37\)
\(\Rightarrow3^x=151\)
\(\Rightarrow x\in\varnothing\)
\(B.\left(x-2\right)5-5=5\)
\(\Rightarrow5x-10=5+5\)
\(\Rightarrow5x=10+10\)
\(\Rightarrow x=20\div5=4\)
188 - 2X = 84
2X = 188 - 84
2X = 104
X = 104 : 2
X = 52
CHÚC bạn học tốt
121-(188-x)=217
188-x=121-217
188-x=-96
x=188-(-96)
x=284
Vậy x\(\in\)(284)
121-(188-x)=217
188-x=121-217
188-x=-96
x=188-(-96)
x=284
\(x-\left(-18\right)=134-\left(34-91\right)\)
⇔\(x+18=134-34+91\)
⇔\(x+18=191\)
⇔\(x=173\)
\(4x+\left(-188\right)=-358+\left(458-124\right)\)
⇔\(4x-188=-358+458-124\)
⇔\(4x-188=-24\)
⇔\(4x=164\)
⇔\(x=41\)
+) x-(-18) = 134 - (34-91)
<=> x +18 = 191
<=> x= 173
+) 4x+(-188) = -358 + (458 - 124)
<=> 4x =164
<=>x =41
a) 1 ≤ x ≤ 6 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1
b) - 7 ≤ x ≤ - 3 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1
\(\left(25\cdot21+25\cdot51\right):36\\ =\left[25\cdot\left(21+51\right)\right]:36\\ =\left(25\cdot72\right):36\\ =1800:36\\ =50\\ \left\{188-\left[33+\left(6^2-7\cdot3\right)\right]\right\}:70\\ =\left\{188-\left[33+\left(36-21\right)\right]\right\}:70\\ =\left[188-\left(33+15\right)\right]:70\\ =\left(188-48\right):70\\ =140:70\\ =2\)
\(\left(x-1\right)\left(15-3x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\15-3x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\3x=15\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=5\end{matrix}\right.\)
\(720:\left[41-\left(2x+5\right)\right]=2^3\cdot5=8\cdot5\\ \Rightarrow720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=720:40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=41-18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=23-5\\ \Rightarrow2x=18\\ \Rightarrow x=18:2\\ \Rightarrow x=9\)
a: \(36=3^2\cdot2^2;60=2^2\cdot3\cdot5;90=3^2\cdot2\cdot5\)
=>\(ƯCLN\left(36;60;90\right)=2\cdot3=6\)
=>\(ƯC\left(36;60;90\right)=Ư\left(6\right)=\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
b: \(45=3^2\cdot5;60=2^2\cdot3\cdot5;150=2\cdot3\cdot5^2\)
=>\(ƯCLN\left(45;60;15\right)=3\cdot5=15\)
\(45⋮x;60⋮x;150⋮x\)
=>\(x\inƯC\left(45;60;150\right)\)
=>\(x\inƯ\left(15\right)\)
mà 5<=x<=10
nên \(x=5\)
c: \(45=3^2\cdot5;54=3^3\cdot2;188=2^2\cdot47\)
=>\(ƯCLN\left(45;54;188\right)=1\)
\(45⋮x;54⋮x;188⋮x\)
=>\(x\inƯC\left(45;54;188\right)\)
=>\(x\inƯ\left(1\right)\)
mà 3<x<8
nên \(x\in\varnothing\)
a, (x - 35)-120=0
x-35=120+0
x-35=120
x=120+35
x=155
b,156-(x+61)=82
x+61=156-82
x+61=74
x=74-61
x=13
c,124+(188-x)=217
188-x=217-124
188-x=93
x=188-93
x=95
a) ( x - 35 ) - 120 = 0
x - 35 = 0 + 120
x - 35 = 120
x = 120 + 35
x = 155
b) 156 - ( x + 61 ) = 82
x + 61 = 156- 82
x + 61 = 74
x = 74 - 61
x = 5
c) 124 + ( 188 - x ) = 217
188 - x = 217 - 124
188 - x = 93
x = 188 - 93
x = 95
K MK NHA BẠN, MK CHẮC ĐÚNG LUN ĐÓ NHA, THANK BẠN NHÌU
\(x=188:-2\)
\(x=-94\)
( - 2 ) . x = 188
x = 188 : - 2
x = - 94