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\(\dfrac{3}{2}\)(\(x\) - \(\dfrac{5}{3}\)) - \(\dfrac{4}{5}\) = \(x\) + 1
\(\dfrac{3}{2}\) \(x\) - \(\dfrac{15}{6}\) - \(\dfrac{4}{5}\) = \(x\) + 1
\(\dfrac{3}{2}\)\(x\) - \(x\) = 1 + \(\dfrac{15}{6}\) + \(\dfrac{4}{5}\)
\(\dfrac{1}{2}\)\(x\) =\(\dfrac{43}{10}\)
\(x\) = \(\dfrac{43}{10}\) \(\times\) 2
\(x\) = \(\dfrac{43}{5}\)
\(\dfrac{3}{2}\left(x-\dfrac{5}{3}\right)-\dfrac{4}{5}=x+1\\ \Rightarrow\dfrac{3.\left(x-\dfrac{5}{3}\right)}{2}-\dfrac{4}{5}=x+1\\ \Rightarrow\dfrac{3x-5}{2}-\dfrac{4}{5}=x+1\Rightarrow\dfrac{5\left(3x-5\right)}{10}-\dfrac{8}{10}=x+1\\ \Rightarrow\dfrac{15x-33}{10}=x+1\\ \Rightarrow\dfrac{15x-33}{10}-x=x+1\\ \Rightarrow\dfrac{15x-33}{10}=x+1-x\\ \Rightarrow5x-33=10\\ \Rightarrow5x=10+33\\\Rightarrow5x=43\\ \Rightarrow x=\dfrac{43}{5} \)
a) x - 1/2 = 3/5
x = 3/5 + 1/2
x = 11/10
b) x - 1/2 = -2/3
x = -2/3 + 1/2
x = -1/6
c) 2/5 - x = 0,25
x = 2/5 - 0,25
x = 2/5 - 1/4
x = 3/20
a/
\(A=1.2+1.2+2.3+2.2+3.4+3.2+...+66.67+66.2=\)
\(=\left(1.2+2.3+3.4+...+66.67\right)+2\left(1+2+3+...+66\right)\)
Đặt
\(B=1+2+3+...+66=\dfrac{66\left(1+66\right)}{2}=2211\)
Đặt
\(C=1.2+2.3+3.4+...+66.67\)
\(3C=1.2.3+2.3.3+3.4.3+...+66.67.3=\)
\(=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+66.67.\left(68-65\right)=\)
\(=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-...-65.66.67+66.67.68=\)
\(=66.67.68\Rightarrow C=\dfrac{66.67.68}{3}=22.67.68\)
\(\Rightarrow A=C+2B\) Bạn tự tính nhé
b/
\(B=2\left(1.50+2.49+3.48+...+25.26\right)=\)
Ta có
\(C=1.50+2.49+3.48+...+25.26=\)
\(\left(50-49\right).50+\left(50-48\right).49+\left(50-47\right).48+...+\left(50-25\right).26=\)
\(=50.50-49.50+50.49-48.49+50.48-47.48+50.26-25.26=\)
\(=50.\left(26+27+28+...+50\right)-\left(25.26+26.27+27.28+...+49.50\right)\)
Ta có
\(D=26+27+28+...+50=\dfrac{25.\left(26+50\right)}{2}=950\)
Ta có
\(E=25.26+26.27+27.28+...+49.50\)
\(3E=25.26.3+26.27.3+27.28.3+...+49.50.3=\)
\(=25.26.\left(27-24\right)+26.27.\left(28-25\right)+...+49.50.\left(51-48\right)=\)
\(=-24.25.26+25.26.27-25.26.27+26.27.28-...-48.49.50+49.50.51=\)
\(=49.50.51-24.25.26\)
\(\Rightarrow E=\dfrac{49.50.51-24.25.26}{3}\)
\(\Rightarrow C=50D-E\)
\(B=2C\)
Bạn tự tính nhé
| x | + | 2x - 3 | = 0 (1)
Ta có \(\hept{\begin{cases}\left|x\right|\ge0\\\left|2x-3\right|\ge0\end{cases}}\forall x\)
\(\Rightarrow\left|x\right|+\left|2x-3\right|\ge0\forall x\) (2)
Từ (1) và (2) => (1) \(\Leftrightarrow\) \(\hept{\begin{cases}\left|x\right|=0\\\left|2x-3\right|=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=0\\2x-3=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=0\\2x=3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=0\\x=\frac{3}{2}\end{cases}}\)
\(\Leftrightarrow x\in\varnothing\)
Vậy \(x\in\varnothing\)
@@ Học tốt
!!! K chắc
400 : { 5 . [ 360 - ( 290 + 2 . 55 )]}
= 400 : { 5 . [ 360 - ( 290 + 2 . 25 )]}
= 400 : { 5 . [ 360 - ( 290 + 50 )]}
= 400 : [ 5 . ( 360 - 340 )]
= 400 : ( 5 . 20 )
= 200 : 100 = 2
240.(x-5) = 22.5-20
\(\Rightarrow\)240.(x-5) = 4 . 5 - 20
\(\Rightarrow\)240.(x-5) = 20 - 20
\(\Rightarrow\)240.(x-5) = 0
\(\Rightarrow\)x-5 = 0 : 240
\(\Rightarrow\)x-5 = 0
\(\Rightarrow\)x = 0 + 5
\(\Rightarrow\)x = 5
\(\Rightarrow\)Vậy x = 5
\(\Rightarrow\)240.(x-5)=0
\(\Rightarrow\)x-5= -240
\(\Rightarrow\)x= -240/-5
\(\Rightarrow\)x=48
vậy x=48 k mik nha !