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231 - ( x - 6 ) = 1339 : 13
231 - ( x - 6 ) = 103
x = 231 - 103 + 6
x = 128 + 6
x = 134
2.x-138=2^3.3^2
2.x-138=8.9
2.x-138=72
2.x=72+138
2.x=210
x=210:2
x=105
vậy x=105
b)231-(x-6)=1339:13
231-(x-6)=103
x-6=231-103
x-6=128
x=128+6
x=134
vậy x=134
nhớ **** cho mình nha
\(231-\left(x-6\right)=1339\div13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x=128+6\)
\(x=134\)
231-(x-6)=1339:13
=> 231-(x-6)=103
=> x-6=231-103
=> x-6=128
=> x=128+6
=> x=134
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
`Answer:`
\(12x-144=0\)
\(\Leftrightarrow12x=144\)
\(\Leftrightarrow x=144:12\)
\(\Leftrightarrow x=12\)
\(5x-32:18=13\)
\(\Leftrightarrow5x-\frac{16}{9}=13\)
\(\Leftrightarrow5x=13+\frac{16}{9}\)
\(\Leftrightarrow5x=\frac{133}{9}\)
\(\Leftrightarrow x=\frac{133}{9}:5\)
\(\Leftrightarrow x=\frac{133}{45}\)
\(3x+6=15\)
\(\Leftrightarrow3x=9\)
\(\Leftrightarrow x=3\)
Bài làm
Bạn hamlon bên dưới không làm được vậy để mình làm cho bạn .
\(\frac{3}{5}.\frac{3}{7}+\frac{3}{5}.\frac{2}{9}-\frac{3}{5}.\frac{3}{11}\)
\(=\frac{3}{5}\left(\frac{3}{7}+\frac{2}{9}-\frac{3}{11}\right)\)
\(=\frac{3}{5}.\left(\frac{297}{693}+\frac{154}{693}-\frac{189}{693}\right)\)
\(=\frac{3}{5}.\frac{262}{693}\)
\(=\frac{262}{1155}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\left(\dfrac{x}{2}-1\right)^3+2=-\dfrac{11}{8}\) phải k bạn nhỉ? `11/8` k có bậc lũy thừa nào `=5` á.
`=>`\(\left(\dfrac{x}{2}-1\right)^3=-\dfrac{11}{8}-2\)
`=>`\(\left(\dfrac{x}{2}-1\right)^3=-\dfrac{27}{8}\)
`=>`\(\left(\dfrac{x}{2}-1\right)^3=\left(-\dfrac{3}{2}\right)^3\)
`=>`\(\dfrac{x}{2}-1=-\dfrac{3}{2}\)
`=>`\(\dfrac{x}{2}=-\dfrac{3}{2}+1\)
`=>`\(\dfrac{x}{2}=-\dfrac{1}{2}\)
`=> x=1`
Vậy, `x=1`
`b)`
\(\left(\dfrac{x}{3}+\dfrac{1}{2}\right)\left(75\%-1\dfrac{1}{2}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{x}{3}+\dfrac{1}{2}=0\\0,75-1\dfrac{1}{2}x=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}=-\dfrac{1}{2}\\-\dfrac{3}{2}x=\dfrac{75}{100}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=-3\\-3x\cdot100=2\cdot75\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\-3x\cdot100=150\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\-3x=1,5\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Vậy, `x={-3/2; -1/2}.`
\(231-2.\left(x-6\right)=1339:13\)
\(231-2x+12=103\)
\(2x+12=128\)
\(2x=116\)
\(x=58\)
Vậy \(x=58\)
231 - 2(x - 6) = 1339 : 13
=> 231 - 2(x - 6) = 103
=> 2(x - 6) = 231 - 103
=> 2(x - 6) = 128
=> x - 6 = 128 : 2
=> x - 6 = 64
=> x = 64 + 6
=> x = 70