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\(=2026-2000:\left[486-2\left(49-6\right)\right]\)
\(=2026-2000:\left[486-2\cdot43\right]\)
\(=2026-2000:\left[486-86\right]\)
\(=2026-2000:400\)
\(=2026-5\)
\(=2021\)
=2026-2000:[486-2.(49-6)]
=2026-2000:[486-2.43]
=2026-2000:[486-86]
=2026-2000:400
=2026-5
=2021
2010 - 2000 : [ 486 - 2( 72 - 6 ) ]
= 2010 - 2000 : [ 486 - 2( 49 - 6 )]
= 2010 - 2000 : [ 486 - 2. 43 ]
= 2010 - 2000 : [ 486 - 86 ]
= 2010 - 2000 : 400
= 2010 - 5
= 2005.
2010-2000:\([\)486-2(72-6)\(]\)=2010-2000:\([\)486-86\(]\)
=2010-2000:400
=2010-5=2005
tính : 3/17 . 6/29 - 3/17 . 35/29 + 2022 3/17
b, 5/6-(1/3+1/2). 20%
c,9.5+(-13,2)+12,5+(-0,8)
a: \(=2011+5\cdot\left[300-10^2\right]\)
\(=2011+5\cdot200\)
=1011
b: \(=695-\left[200+10^2\right]\)
=695-300
=395
a) =2011+5.200
=3011
b)=695-300
=395
c)1=29-5.4
=109
d)=2010-2000:400
=2010-5
=2005
1: \(23+\left(-13\right)+\left(-50\right)\)
\(=23-13-50\)
=10-50
=-40
2: \(-5+15+\left(-123\right)\)
\(=\left(-5+15\right)-123\)
=10-123
=-113
3: \(5871:\left\{928-\left[\left(-82+247\right)\right]\right\}\cdot5\)
\(=5871-\left\{928+82-247\right\}\cdot5\)
\(=5871-763\cdot5=5871-3815=2056\)
4: \(40-\left(4\cdot5^2-3\cdot2^3\right)\)
\(=40-4\cdot5^2+3\cdot2^3\)
\(=40-4\cdot25+3\cdot8\)
=40-100+24
=64-100
=-36
5: \(6^2\cdot5-7^2+149\)
\(=36\cdot5-49+149\)
\(=180+149-49\)
=180+100
=280
6: \(-210:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]+\left(-2022\right)\)
\(=-210:\left[16+3\cdot\left(6+3\cdot4\right)\right]+\left(-2022\right)\)
\(=-210:\left[16+3\cdot18\right]+\left(-2022\right)\)
\(=-210:70-2022\)
=-3-2022
=-2025
7: \(5\cdot2^3+7^{11}:7^9-2023^0\cdot1^8\)
\(=5\cdot8+7^2-1\)
=40+49-1
=39+49
=88
8: \(400:\left\{5\cdot\left[360-\left(290+2\cdot5^2\right)\right]\right\}\)
\(=400:\left\{5\cdot\left[360-290-2\cdot25\right]\right\}\)
\(=400:\left\{5\cdot20\right\}\)
\(=\dfrac{400}{100}=4\)
9: \(75-\left(3\cdot5^2\right)-4\cdot5^3\)
\(=75-3\cdot25-4\cdot5^3\)
=-4*125
=-500
a, \(\dfrac{7}{22}\) - \(\dfrac{15}{23}\) + \(\dfrac{2022}{2023}\) - \(\dfrac{8}{23}\) + \(\dfrac{15}{22}\)
= ( \(\dfrac{7}{22}\) + \(\dfrac{15}{22}\)) - ( \(\dfrac{15}{23}+\dfrac{18}{23}\)) + \(\dfrac{2022}{2023}\)
= \(\dfrac{22}{22}\) - \(\dfrac{23}{23}\) + \(\dfrac{2022}{2023}\)
= 1 - 1 + \(\dfrac{2022}{2023}\)
= \(\dfrac{2022}{2023}\)
b, - \(\dfrac{2}{11}\) + 5\(\dfrac{5}{6}\) ( 14\(\dfrac{1}{5}\) - 11\(\dfrac{1}{5}\)): 5\(\dfrac{1}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) ( \(\dfrac{71}{5}\) - \(\dfrac{56}{5}\)) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) . \(\dfrac{15}{5}\) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{2}\) \(\times\) \(\dfrac{2}{11}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{11}\)
= \(\dfrac{33}{11}\)
= 3
c, 2000 + { 20 - [ 4.20220 - (32 + 5):2] }
= 2000 + { 20 - [ 4.1 - (9+5):2]}
= 2000 + { 20 - [ 4 - 14 : 2 ]}
= 2000 + { 20 - [ 4 -7]}
= 2000 + { 20 - (-3)}
= 2000 + 23
= 2023
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87476845+9
1000 chia hết cho 8 suy ra 10^3 chia hết cho 8
Suy ra:10^25x10^3 chia hết cho 8
và 8 chia hết cho 8
Suy ra 10^28+8 chia hết cho8(1)
Lại có 10^28+8=1000.....08
Suy ra:10^28+8 chia hết 9(2)
Lại vì:ƯCLN(8;9)=1(3)
Suy ra 10^2022+8 chia hết cho 72
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TL
-8907.48898678414 ( Sai thì cho mik xin lỗi )
HT
2017,594714