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1) \(\left(-27\right).\left(-28+128\right)=-27.100=-2700\)
2a)\(\left(x-3\right)\left(2x+6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\2x+6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
b) \(\left(2x-1\right)^2=81\)
\(\sqrt{\left(2x-1\right)^2}=9\)
\(\left|2x-1\right|=9\)
\(\left[{}\begin{matrix}2x-1=9\\2x-1=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-4\end{matrix}\right.\)
c) \(\left(2m+5\right)^3=-27\)
\(\sqrt[3]{\left(2m+5\right)^3}=-3\)
\(2m+5=-3\)
\(m=-4\)
d) \(\left(3x-2\right)^3=64\)
tương tự câu c
( 3x - 1 )^2 = 25 = (+-5)^2
+) 3x - 1 = 5
3x = 6
x = 2
+) 3x - 1 = -5
3x = -4
x = -4/3
Vậy,.........
Các câu còn lại tương tự
a) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
b) \(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
c) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
d) \(x^2=x^3\Rightarrow x^3-x^2=0\Rightarrow x^2\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
e) \(3^{x-1}=27\Rightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
f) \(3^{x+1}=9\Rightarrow3^{x+1}=3^2\Rightarrow x+1=2\Rightarrow x=1\)
g) \(6^{x+1}=36\Rightarrow6^{x+1}=6^2\Rightarrow x+1=2\Rightarrow x=1\)
h) \(3^{2x+1}=27\Rightarrow3^{2x+1}=3^3\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)
i) \(x^{50}=x\Rightarrow x^{50}-x=0\Rightarrow x\left(x^{49}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}=1=1^{49}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
4n = 4096
4n = 212
n = 12
5n = 15625
5n = 56
n = 6
6n+3 = 216
6n+3 = 23.33
6n+3 = 63
n + 3 = 3
\(\left(\frac{1}{3}\right)^{2x-1}-\frac{1}{3^2}=-\frac{2}{27}\)
=> \(\left(\frac{1}{3}\right)^{2x-1}=-\frac{2}{27}+\frac{1}{9}\)
=> \(\left(\frac{1}{3}\right)^{2x-1}=\frac{1}{27}\)
=> \(\left(\frac{1}{3}\right)^{2x-1}=\left(\frac{1}{3}\right)^3\)
=> 2x - 1 = 3
=> 2x = 3 + 1
=> 2x = 4
=> x = 4/2 = 2
a) 3x = 27 (Áp dụng: ax = an (a > 1) => x = n)
3x = 33
x = 3
Vậy x bằng 3
b) 52x = 125 (Áp dụng: ax = an (a > 1) => x = n)
52x = 53
2x = 3
x = 3 : 2
x = 3/2
Vậy x bằng 3/2
c) 4x . 42 = 64
4x . 16 = 43
4x = 43 : 16
4x = 4
x = 1
Vậy x bằng 1
d) 32x : 3 =27
32x : 3 = 33
32x = 33 : 3
32x = 9
32x = 32
2x = 2
x = 1
Vậy x bằng 1
* P/s: Sai cho mình xin lỗi ạ *
Học tốt ~~
1) \(2^8.4.16.32.64.2=2^8.2^2.2^4.2^5.2^6.2=2^{8+2+4+5+6+1}=2^{26}\)
2) \(7.3^x-11=52\Rightarrow7.3^x=52+11=63\)
\(\Rightarrow3^x=63:7=9\Rightarrow3^x=3^2\Rightarrow x=2\)
\(4^{10\left(x+5\right)}=4^{12}\Rightarrow10\left(x+5\right)=12\)
\(\Rightarrow10x+50=12\Rightarrow10x=12-50=-38\)
\(\Rightarrow x=-38:10=-\dfrac{38}{10}=-\dfrac{19}{5}\)
\(7x-2x=6^{17}:6^{15}+2^8:2^6\)
\(\Rightarrow5x=6^2+2^2\Rightarrow5x=36+4=40\)
\(\Rightarrow x=40:5=8\)
\(3^{2x-1}=27\Rightarrow3^{2x-1}=3^3\Rightarrow2x-1=3\)
\(\Rightarrow2x=4\Rightarrow x=4:2=2\)
1) 28. 4 . 16 . 32 . 64
= 28. 22. 24. 25. 26
= 225
a) \(3^2.x+2^3.x=51\)
\(\Leftrightarrow x\left(3^2+2^3\right)=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=3\)
Vậy
b) \(6^2.2-\left(84-3^2.x\right):7=69\)
\(\Leftrightarrow\left(84-3^2.x\right):7=3\)
\(\Leftrightarrow84-3^2.x=21\)
\(\Leftrightarrow3^2.x=63\)
\(\Leftrightarrow x=7\)
Vậy
`#3107.101107`
Mình nghĩ đề phải là \(3^{2x-1}=27\) chứ nhỉ?
\(3^{2x-1}=27\\ \Rightarrow3^{2x-1}=3^3\\ \Rightarrow2x-1=3\\ \Rightarrow2x=3+1\\ \Rightarrow2x=4\\ \Rightarrow x=4\div2\\ \Rightarrow x=2\)
Vậy, `x = 2.`