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a) 97 + 214=311
b) 65 + 129=284
c) 431 - 199=232
e) 42 . 167 - 42 . 67=42 .(167-67)=42 . 100=4200
f) 273 : 13=21
d) 8250 : 250=33
![](https://rs.olm.vn/images/avt/0.png?1311)
1
a.(512-47)-(14-108)-(-57+41)
= 512-47-14+108+57-41
= 465 -122+16
=343+16=359
b. -(-68+15+52)+(-41+27+13)-23-42+34
= +68-15-52-41+27+13-23-42+34
= 1+(-1)-31
=-31
![](https://rs.olm.vn/images/avt/0.png?1311)
TRẢ LỜI:
16=4^2
64=8^2
169=13^2
196=14^2
81=9^2
225=15^2
400=20^2
CHUC BN HOK TOT
![](https://rs.olm.vn/images/avt/0.png?1311)
A = SCSH: ( 102 - 1 ) : 1 + 1 = 102
A = Tổng: ( 102 + 1 ) . 102 : 2 = 5253
Vậy KQ là: 5253
B = SCSH: ( 2998 - 1 ) : 3 + 1 = 1000
B = Tổng: ( 2998 + 1 ) . 1000 : 2 = 1499500
Vậy KQ là 1499500
![](https://rs.olm.vn/images/avt/0.png?1311)
Mk làm bài 3 thoy nha :
Ta có : xy+12=x + y
=> xy - x = y -12
=> x(y-1) = y - 1 - 11
=> x ( y -1 ) - y - 1 = -11
=> ( x- 1) ( y - 1 ) = - 11 = 1 . ( -11 ) = (-11 ) . 1
Ta có bảng :
x - 1 | 1 | -11 |
y - 1 | -11 | 1 |
x | 2 | -10 |
y | -10 | 2 |
Vậy ta tìm đc ( x ; y ) là : ( 2 ; -10 ) ; ( -10 ; 2 )
=)))
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a, 35 + 28 - 42 - 35 - 28
= (35 - 35) + (28 - 28) - 42
= -42
b, 55 +56 +57 +58 +59 -28 -26 -25 -29 -27
=(55-25)+(56-26)+(57-27)+(58-28)+(59-29)
= 30 + 30 + 30 + 30 + 30
= 150
Bài 2:
a, -1983 - (325 - 1983)
= -1983 - 325 + 1983
= -325
b, -549 + (321 + 549)
= -549 + 321 + 549
= 321
c, 54 - (-65 + 98 - 15)
= 54 + 65 - 98 + 15
= 36
d, (67 + 23) - (56 - 32 + 46)
= 67 + 23 - 56 + 32 - 46
= 20
e, 24 - [ 15 - (42 - 18) ]
= 24 - [ 15 - 42 + 18 ]
= 24 - (-9)
= 33
f, (63 - 21 + 84) - (49 - 36 + 87)
= 63 - 21 + 84 - 49 + 36 - 87
= 26
g, 284 - [ (214 - 168) - (865 - 987) ]
= 284 - [ 214 - 168 - 865 + 987 ]
= 284 - 168
= 116
h, 654 + [ (545 - 726) - (321 - 465) ]
= 654 + [ 545 - 726 - 321 + 465 ]
= 654 + (-37)
= 617
Chúc bạn học tốt !
![](https://rs.olm.vn/images/avt/0.png?1311)
mk làm phần a thui nhé
a. A = 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6
A = 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6
A = 1/2 - 1/6
A= 3/6 - 1/6
A = 1/3
\(B=\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+\frac{3}{11\cdot14}\)
\(b=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\)
\(b=\frac{1}{2}-\frac{1}{14}\)
\(b=\frac{3}{7}\)
\(d=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\)
\(d=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{10\cdot11}\)
\(d=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\)
\(d=1-\frac{1}{11}\)
\(d=\frac{10}{11}\)
\(e=\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\)
\(e=\frac{1}{2\cdot5}+\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+\frac{1}{11\cdot14}+\frac{1}{14\cdot17}+\frac{1}{17\cdot20}\)
\(e=\frac{1}{3}\left(\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+...+\frac{3}{17\cdot20}\right)\)
\(e=\frac{1}{3}\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}\right)\)
\(e=\frac{1}{3}\left(\frac{1}{2}-\frac{1}{20}\right)\)
\(e=\frac{1}{3}\cdot\frac{9}{20}=\frac{3}{20}\)
\(a.97+214=311\\ b.65+129=194\\ c.431-199=232\\ d.8250:250=33\\ e.42\cdot167-42\cdot67\\ =42\cdot\left(167-67\right)\\ =42\cdot100\\ =4200\\ f.273:13=21\)