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a) A=625–(61–17).12+(27+27):17A=625–(61–17).12+(27+27):17
=625–528+3=100=625–528+3=100
b) B=−126–(42–5)2+870:29B=−126–(42–5)2+870:29
=−126–112+30=−126–112+30
=−126–121+30=−217
b) 4.(–5)2 + 2.(–5) – 20
= 4.(-5)2 + 2.(-5) - (-4)(-5)
= (-5).[4.(-5) + 2 - (-4)]
= (-5).[-20 + 2 + 4]
=(-5).(-14)
=70
a)125.(-24)+24.225
=(-125).24+24.225
=24.[(-125)+225]
=24.100
=2400
Các câu khác bạn làm tương tự nha
a ) \(125\times\left(-24\right)+24\times225\)
\(=24\left[\left(-125\right)+225\right]\)
\(=24\times100\)
\(=2400\)
b ) \(26\times\left(-125\right)-125\times\left(-36\right)\)
\(=125\left[\left(-26\right)-\left(-36\right)\right]\)
\(=125\times10\)
\(=1250\)
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
2 . tìm x :
a ) 52x = 625
52x = 54
=> 2 . x = 4
x = 4 : 2
x = 2
b ) 9x-1 = 9
9x-1 = 91
=> x - 1 = 1
x = 1 + 1
x = 2
c ) 2x : 25 = 1
2x-5 = 1
=> x = 5 , vì 25-5 = 20 = 1
a: \(=625-44\cdot12+\dfrac{41}{17}=97+\dfrac{41}{17}=\dfrac{1690}{17}\)
b: \(=-126-11^2+30=-126-121+30=-217\)