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![](https://rs.olm.vn/images/avt/0.png?1311)
MSC: 36
Ta có: 5/18 = 5 x 2/ 18 x 2 = 10/36
9/6 = 9 x 6/ 6 x 6 = 54/ 36
7/12 = 7 x 3 / 12 x 3 = 21/36
Được 10/36; 54/36 và 21/36.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3 :
a: \(MSC:12\\ \dfrac{4}{3}=\dfrac{4\times4}{3\times4}=\dfrac{16}{12};\dfrac{3}{4}=\dfrac{3\times3}{3\times4}=\dfrac{9}{12}\)
b: \(MSC:12\\ \dfrac{5}{4}=\dfrac{5\times3}{4\times3}=\dfrac{15}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
c:\(MSC:24\\ \dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24};\dfrac{1}{6}=\dfrac{1\times2}{6\times2}=\dfrac{2}{12}\)
d: \(MSC:35\\ \dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{4}{7}=\dfrac{4\times5}{7\times5}=\dfrac{20}{35}\)
Bài 3:
a: 4/3=16/12
3/4=9/12
b: 5/4=30/24
5/6=20/24
c: 3/8=18/48
1/6=8/48
d: 2/5=14/35
4/7=20/35
Bài 4:
a: 7/12=28/48
5/48=5/48
b: 4/100=4/100
8/25=32/100
![](https://rs.olm.vn/images/avt/0.png?1311)
bài3
1. \(\frac{4}{3}\)= \(\frac{4x4}{3x4}\)=\(\frac{20}{12}\)
\(\frac{3}{4}\)=\(\frac{3x3}{4x3}\)=\(\frac{9}{12}\)
2.\(\frac{5}{4}\)=\(\frac{5x6}{4x6}\)=\(\frac{30}{24}\)
\(\frac{5}{6}\)=\(\frac{5x4}{6x4}\)=\(\frac{20}{24}\)
3.\(\frac{3}{8}\)=\(\frac{3x6}{8x6}\)=\(\frac{18}{48}\)
\(\frac{1}{6}\)=\(\frac{1x6}{6x8}\)=\(\frac{6}{48}\)
4.\(\frac{2}{5}\)=\(\frac{2x7}{5x7}\)=\(\frac{14}{35}\)
\(\frac{4}{7}\)=\(\frac{4x5}{7x5}\)=\(\frac{20}{35}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: 1/3=20/60
1/5=12/60
1/12=5/60
b: 1/3=16/48
1/12=4/48
1/48=1/48
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: 1/3=20/60
1/5=12/60
1/12=5/60
b: 1/3=16/48
1/12=4/48
1/48=1/48
Bài 2:
a: 1/3=20/60
1/5=12/60
1/12=5/60
b: 1/3=16/48
1/12=4/48
1/48=1/48
phân tích ra thừa số nguyên tố
`5=5`
`12=2^2 xx3`
`=>` MSC nhỏ nhất là: `5xx12=60`
`2/5=(2xx12)/(5xx12)=24/60`
`5/12=(5xx5)/(12xx5)=25/60`
\(\dfrac{2}{5};\dfrac{5}{12}\left(MSC=60\right)\)
\(\dfrac{2}{5}=\dfrac{2\times12}{5\times12}=\dfrac{24}{60};\dfrac{5}{12}=\dfrac{5\times5}{12\times5}=\dfrac{25}{60}\)