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Ta có :
\(15^{12}=\left(3.5\right)^{12}=3^{12}.5^{12}\)
\(81^3.125^5=\left(3^4\right)^3.\left(5^3\right)^5=3^{12}.5^{15}\)
Mà \(3^{12}.5^{15}>3^{12}.5^{12}\)
\(\Rightarrow15^{12}< 81^3.125^5\)
15^12 và 81^3.125^5
Ta có:
15^12= (3.5)^ 12= 3^12.5^12
81^3= (3^4)^3= 3^12
125^5= (5^3)^5= 5^15
Suy ra: 81^3.125^5=3^12.5^15
Suy ra: 3^12.5^12 <3^12.5^15 hay 15^12 < 81^3.125^5
15^12=5^12.3^12....81^2.125^5=3^8.5^15....a/b=3^4/5^3<1...vậy 15^12 nhỏ hơn
1512=312.512
813.1255=(34)3.(53)5=312.515
=>1512<813.1255
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a,
15^12=(3*5)^12=3^12*5^12
81^3*125^5=(3^4)^3*(5^3)^5=3^12*5^15
Vì 12<15 suy ra 5^12<5^15
Suy ra 3^12*5^12<3^12*5^15
\(a.81^3.125^5=\left(3^4\right)^3.\left(5^3\right)^5=3^{12}.5^{15}=3^{12}.5^{12}.5^3=\left(3.5\right)^{12}.5^3=15^{12}.5^3>15^{12}\)
\(b.4^{20}.81^{12}=\left(2^2\right)^{20}.\left(9^2\right)^{12}=2^{40}.9^{24}=2^{20}.2^{20}.9^{20}.9^4=\left(2.9\right)^{20}.2^{20}.9^4=18^{20}.2^{20}.9^4>18^{20}\)
\(c.73^{75}=\left(73^3\right)^{25}=389017^{25}\)
\(107^{50}=107^{2.50}=\left(107^2\right)^{25}=11449^{25}\)
Vì \(389017^{25}>11449^{25}\Rightarrow73^{75}>107^{50}\)
a: \(125^{18}=5^{54}=25^{27}\)
\(3^{81}=27^{27}\)
mà 25<27
nên \(125^{18}< 3^{81}\)
b: \(81^3\cdot125^5=3^{12}\cdot5^{15}\)
\(15^{12}=3^{12}\cdot5^{12}\)
Do đó: \(15^{12}< 81^3\cdot125^5\)
Ta có:
\(15^{12}=\left(3\cdot5\right)^{12}=3^{12}\cdot5^{12}\)
\(81^3\cdot125^5=\left(3^4\right)^3\cdot\left(5^3\right)^5=3^{12}\cdot5^{15}\)
Mà: \(15>12\)
\(\Rightarrow5^{15}>5^{12}\)
\(\Rightarrow3^{12}\cdot5^{15}>3^{12}\cdot5^{12}\)
\(\Rightarrow81^3\cdot125^5>15^{12}\)