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Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
a) \(12^7:6^7=\left(12:6\right)^7=2^7\)
b) \(27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3=27\)
c) \(18^3:9^3=\left(18:9\right)^3=2^3=8\)
d) \(125^3:25^4=\left(5^3\right)^3:\left(5^2\right)^4=5^9:5^8=5\)
a, 127 : 67 = (12 : 6)7 = 27 = 128.
b,275 : 813 = (33)5 : (34)3 = 315 : 312 = 315 - 12 = 33 = 27
c,183 : 93 = (18 : 9)3 = 23 = 8.
d, 1253 : 254 = (53)3 : (52)4 = 59 : 58 = 59 - 8 = 5.
\(4^8.2^{20}=2^{16}.2^{20}=2^{36}\)
\(9^{12}.27^5.81^4=3^{24}.3^{15}.3^{16}=3^{55}\)
mk chỉnh đề
\(64^3.4^5.16^2=4^9.4^5.4^4=4^{18}\)
\(25^{20}.125^4=5^{40}.5^{12}=5^{52}\)
\(x^7.x^4.x^3=x^{14}\)
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
a, \(\frac{6^5\cdot27^2}{7^3\cdot9^5}=\frac{2^5\cdot3^5\cdot\left(3^3\right)^2}{7^3\cdot\left(3^2\right)^5}=\frac{2^5\cdot3^5\cdot3^6}{7^3\cdot3^{10}}=\frac{2^5\cdot3^{11}}{7^3\cdot3^{10}}=\frac{2^5\cdot3}{7^3}\)
b, \(\frac{12^7\cdot9^3}{8^5\cdot27^3}=\frac{3^7\cdot2^{12}\cdot3^6}{2^{15}\cdot3^9}=\frac{2^{12}\cdot3^{13}}{2^{15}\cdot3^9}=\frac{3^4}{2^3}\)
c, \(\frac{20^6\cdot8^2}{16^3\cdot25^3}=\frac{2^{12}\cdot5^6\cdot2^6}{2^{12}\cdot5^6}=2^6\)
24 . 26 . 2 = 211
35 . 27 . 81 . 36 = 35 . 33 . 34 . 36 = 318
42 . 415 . 64 = 42 . 415 . 43 = 420
29 . 16 . 48 = 29 . 24 . (22)8 = 29 . 24 . 216 = 229
512 : 54 = 58
274 : 34 = (27:3)4 = 94
\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
6 mũ 0
con thứ 2 mình chịu
9 mũ 0
.,mhvj
127 : 67 = ( 12:6)7 = 27
275 : 813 = ( 33)5 : ( 34)3 = 315 : 312 = 315-12 = 33
183 : 93 = ( 18:9)3= 23
1253: 254= ( 53)3: ( 52)4= 59 : 58 = 59-8 = 5