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Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{7}{3\cdot3}\cdot\dfrac{3}{7\cdot5}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9}{11\cdot2}\cdot11\cdot5=\dfrac{45}{2}\)
\(\dfrac{11}{17}:\dfrac{33}{34}=\dfrac{11}{17}\cdot\dfrac{34}{33}=\dfrac{11\cdot17\cdot2}{17\cdot11\cdot3}=\dfrac{2}{3}\)
\(\dfrac{33}{38}:\dfrac{11}{19}=\dfrac{33\times19}{38\times11}=\dfrac{3\times1}{2\times1}=\dfrac{3}{2}\)
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
a)\(\frac{8}{3}\)
b)\(\frac{1}{5}=0,2\)
c)\(\frac{17}{135}\)
d)\(\frac{2}{3}\)
e)\(\frac{5}{2}=2,5\)
11/17 : 33/34 = 11/17 x 34/33
= 11 x 17 x 2 / 17 x 11 x 3
= 2/3
mk có thể làm bài này theo cách rút gọn bạn nhé !
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{2}{3}\)
. = x
Thấy 28%=\(\frac{7}{25}\)33%=\(\frac{33}{100}\)17%=\(\frac{17}{100}\)
Vậy ta có phép tính \(\frac{7}{25}+\frac{11}{50}+\frac{17}{100}+\frac{33}{100}\)
Ta có: \(\left(\frac{7}{25}+\frac{11}{50}\right)+\left(\frac{17}{100}+\frac{33}{100}\right)\)
=\(\frac{6}{25}+\frac{1}{2}\)=\(\frac{37}{50}\)
`11/17 : 33/3`
`=11/17 : 11`
`=11/17 xx 1/11`
`=(11xx1)/(17xx11)`
`= 1/17`
= 11/17 : 11/1
= 11/17 x 1/11
=11/187