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LM
Lê Minh Vũ
CTVHS VIP
14 tháng 9 2021

\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\left(\frac{2}{5}+x\right)=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{3}{12}\)

\(x=\frac{3}{12}-\frac{2}{5}\)

\(x=-\frac{3}{20}\)

6 tháng 2 2021

\(\dfrac{3}{2}x+\dfrac{3}{7}=-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{3}{2}x=-\dfrac{43}{35}\)

\(\Leftrightarrow x=-\dfrac{86}{105}\)

Vậy \(x=-\dfrac{86}{105}\)

\(-\dfrac{11}{12}x+0,25=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x=\dfrac{7}{12}\)

\(\Leftrightarrow x=-\dfrac{7}{11}\)

Vậy \(x=-\dfrac{7}{11}\)

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left(x-2\right)^2-1=0\)

\(\Leftrightarrow\left(x-2-1\right)\left(x-2+1\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = {3; 1}\(\left(2x-1\right)^3=-8\)

\(\Leftrightarrow2x-1=-2\)

\(\Leftrightarrow2x=-1\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

6 tháng 2 2021

       (x - 2)2 = 1

<=>\(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = 3; 1

(2x - 1)= -8

<=> 2x - 1 = -2

<=> 2x = -1

<=> x = \(\dfrac{-1}{2}\)

Vậy x = \(\dfrac{-1}{2}\)

24 tháng 7 2023

\(-\dfrac{3}{4}.\dfrac{4}{11}+\left(-\dfrac{5}{4}\right).\dfrac{4}{11}=\dfrac{4}{11}\left(-\dfrac{3}{4}-\dfrac{4}{4}\right)=\dfrac{4}{11}.\left(-\dfrac{4}{7}\right)=-\dfrac{16}{77}\)

\(\dfrac{7}{12}-\left(-\dfrac{1}{5}\right)-\dfrac{5}{6}+\dfrac{2}{3}+\left(-\dfrac{1}{5}\right)\)

\(=\dfrac{7}{12}+\dfrac{1}{5}-\dfrac{5}{6}+\dfrac{2}{3}-\dfrac{1}{5}\)

\(=\dfrac{7}{12}-\dfrac{5}{6}+\dfrac{2}{3}=\dfrac{7}{12}-\dfrac{10}{12}+\dfrac{8}{12}=\dfrac{5}{12}\)

24 tháng 7 2023

giúp với

21 tháng 9 2021

a. \(x-\dfrac{2}{35}=\dfrac{-2}{25}\)

<=> \(x=\dfrac{-2}{25}+\dfrac{2}{35}\)

<=> x = \(-\dfrac{4}{175}\)

b. \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)

<=> \(\dfrac{11}{12}-x-\dfrac{2}{5}=\dfrac{2}{3}\)

<=> \(-x=\dfrac{2}{3}-\dfrac{11}{12}+\dfrac{2}{5}\)

<=> \(-x=\dfrac{3}{20}\)

<=> \(x=\dfrac{-3}{20}\)

c. \(\dfrac{2}{5}+\dfrac{1}{4}x=\dfrac{-3}{10}\)

<=> \(\dfrac{1}{4}x=\dfrac{-3}{10}-\dfrac{2}{5}\)

<=> \(\dfrac{1}{4}x=\dfrac{-7}{10}\)

<=> \(x=\dfrac{-14}{5}\)

21 tháng 9 2021

a) \(x-\dfrac{2}{35}=-\dfrac{2}{25}\)

\(\Rightarrow x=-\dfrac{2}{25}+\dfrac{2}{35}\)

\(\Rightarrow x=-\dfrac{4}{175}\)

b) \(\dfrac{11}{12}-\left(x+\dfrac{2}{5}\right)=\dfrac{2}{3}\)

\(\Rightarrow x+\dfrac{2}{5}=\dfrac{11}{12}-\dfrac{2}{3}\)

\(\Rightarrow x+\dfrac{2}{5}=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}\)

\(\Rightarrow x=-\dfrac{3}{20}\)

c) \(\dfrac{2}{5}+\dfrac{1}{4}x=-\dfrac{3}{10}\)

\(\Rightarrow\dfrac{1}{4}x=-\dfrac{3}{10}-\dfrac{2}{5}\)

\(\Rightarrow\dfrac{1}{4}x=-\dfrac{7}{10}\)

\(\Rightarrow x=-\dfrac{7}{10}:\dfrac{1}{4}\)

\(\Rightarrow x=-\dfrac{14}{5}\)

19 tháng 9 2021

\(a,\Rightarrow\dfrac{2}{5}+x=\dfrac{11}{12}-\dfrac{2}{3}=\dfrac{1}{4}\Rightarrow x=\dfrac{1}{4}-\dfrac{2}{5}=-\dfrac{3}{20}\\ b,\Rightarrow\left[{}\begin{matrix}x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\\ c,\Rightarrow\dfrac{1}{4}:x=-\dfrac{2}{5}-\dfrac{3}{4}=-\dfrac{23}{20}\\ \Rightarrow x=\dfrac{1}{4}:\left(-\dfrac{23}{20}\right)=-\dfrac{5}{23}\)

7 tháng 7 2016

2/5 + x = 11/12 - 2/3 ​

​2/5 + x = 1/4

​x = 1/4 - 2/5

​x = -3/20.Vậy x= -3/20

16 tháng 5 2022

a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)

16 tháng 5 2022

b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)

25 tháng 12 2016

\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{1}{4}\)

\(x=\frac{2}{5}-\frac{1}{4}\)

\(x=\frac{3}{20}\)

25 tháng 12 2016

\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\Rightarrow\frac{2}{5}+x=\frac{1}{4}\)

\(\Rightarrow x=\frac{-3}{20}\)

Vậy \(x=\frac{-3}{20}\)

17 tháng 6 2017

\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{8}{12}\)

\(\frac{2}{5}+x=\frac{1}{4}\)

\(x=\frac{1}{4}-\frac{2}{5}\)

\(x=\frac{5}{20}-\frac{8}{20}\)

\(x=-\frac{3}{20}\)

17 tháng 6 2017

11/12-(2/5+x)=2/3

2/5+x=11/12-2/3

2/5+x=1/4

x=1/4-2/5

x=-3/20