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a) \(\frac{2^{11}.9^2}{3^5.16^2}=\frac{2^{11}.3^4}{3^5.2^8}=\frac{2^3}{3}=\frac{8}{3}\)
:V Làm sai hết rồi sai ngay từ bước đầu tiên.
\(\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-....-\frac{1}{9.10}\)
\(=\frac{1}{3.4}-\left(\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{9.10}\right)\)
\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{10}\right)\)
\(=\frac{1}{12}-\frac{3}{20}\)
\(=\frac{-11}{12}\)
\(\frac{1}{3.4}-\frac{1}{4.5}-...-\frac{1}{9.10}\)
= \(-\left(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)
= \(-\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)
= \(-\left(\frac{1}{3}-\frac{1}{10}\right)\)
= \(-\frac{7}{30}\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}=\frac{2^{15}.3^8}{2^{15}.3^6}=\frac{3^8}{3^6}=3^2=9\)
\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^9.2^6.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^9.2^6.3^8}{2^9.2^6.3^6}=\frac{2^9.2^6.3^6.3^2}{2^9.2^6.3^6}=3^2=9\)
\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{2^6.3^6.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^6.3^6.2^9}=\dfrac{2^{15}.3^8}{2^{15}.3^6}=\dfrac{1.3^2}{1.1}=3^2=9\)
Chúc Bạn Học Tốt!!!
- Ta có:
\(\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{2^{15}.\left(3^2\right)^4}{2^6.3^6.\left(2^3\right)^3}=\dfrac{2^{15}.3^8}{2^6.3^6.2^9}=\dfrac{2^{15}.3^8}{2^{15}.3^6}=3^2\)
- Vậy \(\dfrac{2^{15}.9^4}{6^6.8^3}=3^2\)
a.=[ \(\frac{1}{5}\)x 5 ]5 b. \(\frac{102^3}{40^3}\)=[ \(\frac{102}{40}\)]3 c.=\(\frac{75^{10}.5^{20}}{75^{10}.75^5}\)=\(\frac{5^{20}}{75^5}\)
=15 =[ \(\frac{51}{20}\)]3
=1
\(\frac{45^{10}\times5^{20}}{75^{15}}=243\)
mk ko nhớ cách giải, chỉ có kết quả, nếu đúng k cho mk nha