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(2/3.5/7 + 2/3: 7/2). -1/3
=(10/21 + 2/3x2/7 ) . -1/3
=(10/21 + 4/21) . -1/3
=-10/63 - 4/63
=-14/63
(2/3.5/7+2/3:7/2)-1/3
=(2/3.5/7+2/3x2/7)-1/3
=[2/3.(5/7+2/7)]-1/3
=[2/3x1]-1/3
=2/3-1/3
=1/3
HT
=[\(\left(\frac{2}{3}.\frac{5}{7}+\frac{2}{3}.\frac{2}{7}\right).\left(\frac{-1}{3}\right)\)]
=[\(\left(\frac{2}{3}\right).\left(\frac{5}{7}+\frac{2}{7}\right).\left(\frac{-1}{3}\right)\)]
=[\(\left(\frac{2}{3}.1\right).\frac{-1}{3}\)]
=\(\frac{-1}{3}\)
a) = 397( 52 + 49 - 1 )
= 397.100
= 39700
b) = 197( 52 + 47 + 1 )
= 197.100
= 19700
c) 456 . 1001
= 456.1000 + 456
= 456000 + 456
= 456456
a) 397.52+397.49-397
= 397 . ( 52 + 49 - 1 )
= 397 . 100 = 39700
b) 197.52+197.47+197
= 197 . ( 52 + 47 + 1
= 197 . 100 = 19700
c) 456.1001
= 456 . ( 1000 + 1 )
= 456 . 1000 + 456 . 1
= 456000 + 456
= 456456
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
1)
a: (36-16).(-5)+6.(-14-6)
=20.(-5)+6.(-20)
=20.(-5)+(-6).20
=20.(-5+-6)
=20.(-11)
=-220
2)
a/x+(-23)=(-100)+77
x+(-23)=-23
x=(-23)+(-23)
x=0
Vậy x=0
\(-23\cdot63+23\cdot21-58\cdot23\)
\(=23\left(-63+21-58\right)\)
\(=23\cdot\left(-100\right)\)
\(=-2300\)
\(=\dfrac{11}{4}\cdot\left(-1\right)\cdot\dfrac{8}{33}=\dfrac{2}{3}\cdot\left(-1\right)=-\dfrac{2}{3}\)
a) \(0,6+\dfrac{2}{3}=\dfrac{6}{10}+\dfrac{2}{3}=\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{19}{15}\)
b) \(-\dfrac{5}{12}+0,75=-\dfrac{5}{12}+\dfrac{75}{100}=-\dfrac{5}{12}+\dfrac{3}{4}=-\dfrac{5}{12}+\dfrac{9}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)
c) \(\dfrac{1}{3}-\left(-0,4\right)=\dfrac{1}{3}+\dfrac{4}{10}=\dfrac{1}{3}+\dfrac{2}{5}=\dfrac{5}{15}+\dfrac{6}{15}=\dfrac{11}{15}\)
d) \(1\dfrac{3}{5}+\dfrac{5}{6}=\dfrac{8}{5}+\dfrac{5}{6}=\dfrac{48}{40}+\dfrac{25}{30}=\dfrac{73}{30}\)
a, 5.72.10.2
= 5.2.10.72
=10.10.72
=7200
b, 40.125
= 40.25.5
=1000.5
=5000
c, 4.2021.25
= 4.25.2021
=100.2021
=202100
d, 16.6.25
= 4.4.6.25
=4.25.24
=100.24
=2400