Question

[Đinh Trần Diệu Linh]

1 + 4y / 13 = 1 + 6y / 19 = 1 + 8y / 5x 

Answer 1

[Xyz OLM]

Ta có\(\frac{1+4y}{13}=\frac{1+6y}{19}=\frac{1+8y}{5x}=\frac{1+4y+1+8y}{13+5x}=\frac{2\left(1+6y\right)}{13+5x}\)

=> \(\frac{1+6y}{19}=\frac{2\left(1+6y\right)}{13+5x}\)

=> 2(1 + 6y).19 = (13 + 5x).(1 + 6y)

=> 38 = 13 + 5x

<=> 25 = 5x

<=> x = 5

Khi đó \(\frac{1+4y}{13}=\frac{1+6y}{19}\)

<=> (1 + 4y).19 = (1 + 6y).13

<=> 19 + 76y = 13 + 78y 

<=> 6 = 2y

<=> y = 3

Vậy y = 3 ; x = 5