Tính A =4/2*5+4/5*8+4/8*11+...+4/65*68
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\(9+2+5+3+7+8+4+2+9+6+4+65+6+7+4+6+3+7+4+8+5+9+08+87+1+2+3+4+2+3+2+5+6+767+5+75+6+4+6+5+66+5+7+546+46+43+6+3+6+4+6+7+8878+68+68+6+7+9+9=10961\)
Ý bạn là mỗi phép tính phải thêm dấu và ....để kết quả bằng 6 phải không ạ
2/
a)\(\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{4}{11}+\dfrac{7}{11}\)
= \(\dfrac{5}{5}+\dfrac{11}{11}\)
= \(1+1\)
= \(2\)
b) \(\left(\dfrac{1}{8}+\dfrac{3}{8}\right)+\left(\dfrac{4}{12}+\dfrac{5}{12}\right)\)
= \(\dfrac{4}{8}+\dfrac{8}{12}\)
= \(\dfrac{12}{24}+\dfrac{16}{24}\)
= \(\dfrac{28}{24}\)
= \(\dfrac{7}{6}\)
a: \(=\dfrac{7}{2}\left(-\dfrac{3}{4}+\dfrac{5}{13}-\dfrac{9}{4}-\dfrac{8}{13}\right)=\dfrac{7}{2}\cdot\left(-3-\dfrac{3}{13}\right)=\dfrac{7}{2}\cdot\dfrac{-42}{13}=\dfrac{-147}{13}\)
b: \(=-12+\dfrac{8}{9}-\dfrac{5}{18}=\dfrac{-216}{18}+\dfrac{16}{18}-\dfrac{5}{18}=\dfrac{-205}{18}\)
c: \(=\dfrac{45}{4}-\dfrac{19}{7}-\dfrac{21}{4}=6-\dfrac{19}{7}=\dfrac{23}{7}\)
d: \(=\dfrac{-1}{4}\left(\dfrac{152}{11}+\dfrac{68}{11}\right)=\dfrac{-1}{4}\cdot20=-5\)
\(A=\frac{4}{2.5}+\frac{4}{5.8}+\frac{4}{8.11}+...+\frac{4}{65.68}\)
\(A=4\left(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{65.68}\right)\)
\(A=\frac{4}{3}\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{65}-\frac{1}{68}\right)\)
\(A=\frac{4}{3}\left(\frac{1}{2}-\frac{1}{68}\right)\)
\(A=\frac{4}{3}.\frac{33}{68}\)
\(A=\frac{11}{17}\)
A = \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)\(\frac{4}{2.5}+\frac{4}{5.8}+\frac{4}{8.11}+.......+\frac{4}{65.68}\)\(\)4/2x5 + 4/5x8 + 4/8x11 + ....... + 4/65x68
Nhân cả 2 vế với 3/4 ta có :
3/4A = \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)\(\frac{4}{2.5}+\frac{4}{5.8}+\frac{4}{8.11}+.......+\frac{4}{65.68}\)\(\)3/2x5 + 3/5x8 + 3/8x11 + ....... + 3/65x68
3/4A = 1/2-1/5 + 1/5 - 1/8 + 1/8 - 1/11 + ........ + 1/65 - 1/68
3/4A = 1/2 - 1/68
3/4A = 33/68
A = 33/68 : 3/4
A = 11/17