Tính M= \(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
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\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)
Chúc học tốt :)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)
\(M=\frac{2^{20}}{2^{12}}\)
\(M=2^8=256\)
\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)
Vậy
\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)
P/s; Ko chắc đâu nhé
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8\)
tách 8 thành 2 mũ 3, 4 thành 2 mũ 2 là sẽ ra nhé
đáp án là 2 mũ 8
\(M=\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)
\(=\sqrt{\frac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)
\(=\sqrt{\frac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}\)
\(=\sqrt{\frac{2^{20}}{2^{12}}}\)
\(=\sqrt{2^8}\)
\(=2^4\)
\(=16\)
=.= hok tốt!!
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\frac{8^4+4^{10}.8^6}{8^4+4^{10}.4}\)
\(M=1\frac{8^6}{8^4+4^{10}.4}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}\left(2^{18}+2^8\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{18}+2^8}{1+2^{10}}\)
\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.2^8\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^8\)