tính bằng cách thuận tiện a)127x23+127x43+127x33+127,b)5/4x2/3+5/4x7/3+7/5
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a, (1 + 3 + 5 + 7+ ... + 2003 + 2005) x (125125 x 127 - 127127 x125)
= (1 + 3 + 5 +...+2003 + 2005) x (125 x 1001 x 127 - 127x1001 x 125)
= (1 + 3 + 5 +...+ 2003 + 2005) x 0
= 0
a, \(=\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\left(\dfrac{3}{5}+\dfrac{3}{5}\right)=1+\dfrac{6}{5}=\dfrac{5+6}{5}=\dfrac{11}{5}\)
\(a,\dfrac{47}{3}:3-\dfrac{37}{3}:3+\dfrac{5}{3}=\dfrac{1}{3}\times\left(\dfrac{47}{3}-\dfrac{37}{3}\right)+\dfrac{5}{3}=\dfrac{10}{9}+\dfrac{5}{3}=\dfrac{10}{9}+\dfrac{15}{9}=\dfrac{25}{9}\)
\(b,\dfrac{3}{5}:\dfrac{7}{9}\times\dfrac{7}{9}:2=\dfrac{27}{35}\times\dfrac{7}{18}=\dfrac{3}{10}\)
a)
`127+246+273+354`
`=(127+273)+(246+354)`
`=400+600`
`=1000`
b)
`1,58+3,04+6,96+3,42`
`=(1,58+3,42)+(3,04+6,96)`
`=5+10`
`=15`
c)
`1/2+1/3+1/5+1/6`
`=(1/2+1/3+1/6)+1/5`
`=(3/6+2/6+1/6)+1/5`
`=6/6+1/5`
`=1+1/5`
`=5/5+1/5`
`=6/5`
a, 127 + 246 + 273 + 354
= ( 127 + 273) + ( 246 + 354)
= 400 + 600
= 1000
b, 1,58 + 3,04 + 6,96 + 3,42
= ( 1,58 + 3,42) + ( 3,04 + 6,96)
= 5 + 10
= 15
c, \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{5}\) + \(\dfrac{1}{6}\)
= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\)) + 0,2
= 1 + 0,2
= 1,2
a) 3 2/7 - 2/5 + 5/7 - 3/5
= 3 + 2/7 - (2/5 + 3/5) + 5/7
= 3 + (2/7 + 5/7) - 1
= 3 + 1 - 1
= 3
b) 5 4/7 - 4/9 + 1 3/7 - 5/9
= 5 + 4/7 - 4/9 + 1 + 3/7 - 5/9
= (5 + 1) + (4/7 + 3/7) - (4/9 + 5/9)
= 6 + 1 - 1
= 6
a) \(3\dfrac{2}{7}-\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{3}{5}\)
\(=\left(\dfrac{23}{7}+\dfrac{5}{7}\right)-\left(\dfrac{2}{5}+\dfrac{3}{5}\right)\)
\(=4-1\)
\(=3\)
b) \(5\dfrac{4}{7}-\dfrac{4}{9}+1\dfrac{3}{7}-\dfrac{5}{9}\)
\(=\left(\dfrac{32}{7}+\dfrac{10}{7}\right)-\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)
\(=6-1\)
\(=5\)
a) ( 2/5 + 3/5) + 7/8
= 5/5 +7/8
= 1+ 7/8
=15/8 ( tính lại hộ mk nha, sợ ko đúng)
b)( 19/11 + 3/11 ) + 5/13
= 22/11 +5/13
= 2 + 5/13
= ...( bn tính nốt nha, vì mk ko có nháp ở đây )
k nha!!!
a) (2/5 + 7/8) + 3/5
= 2/5 + 7/8 + 3/5
= (2/5 + 3/5) + 7/8
= 1 + 7/8
= \(1\frac{7}{8}\)
b) 19/11 + (5/13 + 3/11)
= 19/11 + 5/13 + 3/11
= (19/11 + 3/11) + 5/13
= 2 + 5/13
= \(2\frac{5}{13}\)
\(a,127\times23+127\times43+127\times33+127\)
\(=127\times23+127\times43+127\times33+127\times1\)
\(=127\times\left(23+43+33+1\right)\)
\(=127\times100\)
\(=12700\)
\(b,\dfrac{5}{4}\times\dfrac{2}{3}+\dfrac{5}{4}\times\dfrac{7}{3}+\dfrac{7}{5}\)
\(=\dfrac{5}{4}\times\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\dfrac{7}{5}\)
\(=\dfrac{5}{4}\times3+\dfrac{7}{5}\)
\(=\dfrac{15}{4}+\dfrac{7}{5}\)
\(=\dfrac{75}{20}+\dfrac{28}{20}\)
\(=\dfrac{103}{20}\)
a) 127(23+43+33+1)
= 127.100
=12700
b) \(\dfrac{5}{4}.\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\dfrac{7}{5}\)
=\(\dfrac{15}{4}+\dfrac{7}{5}\)
= \(\dfrac{103}{20}\)