11/35 + 3/4 +24/35 +5/4 tính bằng cách thuận tiện
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\(25\times35\times11\times4\)
\(=\left(35\times11\right)\times\left(25\times4\right)\)
\(=385\times100\)
\(=38500\)
a: =1h15p+4h45p+2h24p+3h36p
=6h+6h
=12h
b: =2,5h+4,5h+5h
=7h+5h
=12h
c: =10h-8h=2h
\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)
a: Ta có: 24+35+76+65+22
=(24+76)+(35+65)+22
=222
b: Sửa đề: \(24\cdot35+24\cdot65\)
=24x100
=2400
\(\frac{37}{35}:\frac{5}{4}:\frac{74}{25}\)
\(=\frac{37}{35}:\left(\frac{5}{4}\times\frac{74}{25}\right)\)
\(=\frac{37}{35}:\frac{37}{10}\)
\(=\frac{2}{7}\)
\(\frac{37}{35}:\frac{5}{4}:\frac{74}{25}\)
=\(\frac{37}{35}x\frac{4}{5}x\frac{25}{74}\)
\(=\left(\frac{37}{35}x\frac{25}{74}\right)x\frac{4}{5}\)
\(=\frac{1}{7}x\frac{5}{2}x\frac{4}{5}\)
\(=\frac{1x5x2x2}{7x2x5}\)
\(=\frac{2}{7}\)
17/35 nhân 9/5 nhân 4/5
= 17/35 nhân ( 9/5 nhân 4/5 )
= 17/35 nhân 13/5
= 221/175
\(\dfrac{14}{21}\times\dfrac{2}{11}+\dfrac{1}{11}:\dfrac{3}{2}+\dfrac{2}{3}:\dfrac{11}{4}+\dfrac{4}{11}\times\dfrac{16}{24}\\ =\dfrac{2}{3}\times\dfrac{2}{11}+\dfrac{1}{11}\times\dfrac{2}{3}+\dfrac{2}{3}\times\dfrac{4}{11}+\dfrac{4}{11}\times\dfrac{2}{3}\\ =\dfrac{2}{3}\times\left(\dfrac{2}{11}+\dfrac{1}{11}+\dfrac{4}{11}+\dfrac{4}{11}\right)\\ =\dfrac{2}{3}\times\dfrac{2+1+4+4}{11}\\ =\dfrac{2}{3}\times\dfrac{11}{11}=\dfrac{2}{3}\times1=\dfrac{2}{3}\)
\(\dfrac{11}{35}+\dfrac{3}{4}+\dfrac{24}{35}+\dfrac{5}{4}\)
\(=\left(\dfrac{11}{35}+\dfrac{24}{35}\right)+\left(\dfrac{3}{4}+\dfrac{5}{4}\right)\)
=1+2
=3
`11/35 + 3/4 + 24/35 + 5/4`
`= (11/35 + 24/35) + (3/4 + 5/4)`
`= 1 + 2`
`= 3`