Question

[Vũ Khải Minh]

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\left(\dfrac{2}{3}\right)^6\cdot\left(\dfrac{8}{27}\right)^2=\left(\dfrac{2}{3}\right)^6\cdot\left(\dfrac{2}{3}\right)^6=\left(\dfrac{2}{3}\right)^{12}\)

b: \(\left(\dfrac{3}{5}\right)^2\cdot\left(-\dfrac{9}{25}\right)^2=\left(\dfrac{3}{5}\right)^2\cdot\left(\dfrac{9}{25}\right)^2\)

\(=\left(\dfrac{3}{5}\right)^2\cdot\left(\dfrac{3}{5}\right)^4=\left(\dfrac{3}{5}\right)^6\)

c: \(\left(-\dfrac{5}{2}\right)^3:\left(-\dfrac{8}{125}\right)^3\)

\(=\left(-\dfrac{5}{2}:\dfrac{-8}{125}\right)^3=\left(\dfrac{5}{2}\cdot\dfrac{125}{8}\right)^3=\left(\dfrac{625}{16}\right)^3\)

\(=\left(\dfrac{5}{2}\right)^{12}\)