Tìm x:
(2x+3)3=73
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`#040911`
\(2^x+2^{x-3}-2^{x+5}=73\)
\(\Rightarrow2^x+2^x\div2^3-2^x\cdot2^5=73\\ \Rightarrow2^x+2^x\cdot\dfrac{1}{8}-2^x\cdot2^5=73\\ \Rightarrow2^x\cdot\left(1+\dfrac{1}{8}-2^5\right)=73\\ \Rightarrow2^x\cdot\left(-\dfrac{247}{8}\right)=73\\ \Rightarrow2^x=73\div\left(-\dfrac{247}{8}\right)\\ \Rightarrow2^x=-\dfrac{584}{247}\)
Bạn xem lại đề.
=>|73-|2x+1||=17+3=20
=>73-|2x+1|=20 hoặc 73-|2x+1|=-20
=>|2x+1|=53 hoặc |2x+1|=93
\(\Leftrightarrow2x+1\in\left\{53;-53;93;-93\right\}\)
hay \(x\in\left\{26;-27;46;-47\right\}\)
x - 48 : 3 = 12
x - 16 = 12
x = 12 + 16
x = 28
còn câu thứ 2 thì chia có dư bạn xem lại xem có chép sai đầu bài ko
Lời giải:
1. $(x+2)-2=0$
$x+2=2$
$x=0$
2.
$(x+3)+1=7$
$x+3=7-1=6$
$x=6-3=3$
3.
$(3x-4)+4=12$
$3x-4+4=12$
$3x=12$
$x=12:3=4$
4.
$(5x+4)-1=13$
$5x+4=13+1=14$
$5x=14-4=10$
$x=10:5=2$
5.
$(4x-8)-3=5$
$4x-8=5+3=8$
$4x=8+8=16$
$x=16:4=4$
6.
$3+(x-5)=7$
$x-5=7-3=4$
$x=4+5=9$
7.
$8-(2x-4)=2$
$2x-4=8-2=6$
$2x=6+4=10$
$x=10:2=5$
8.
$7+(5x+2)=14$
$5x+2=14-7=7$
$5x=7-2=5$
$x=5:5=1$
9.
$5-(3x-11)=1$
$3x-11=5-1=4$
$3x=11+4=15$
$x=15:3=5$
10.
$16-(8x+2)=6$
$8x+2=16-6=10$
$8x=10-2=8$
$x=8:8=1$
a: \(575-\left(2x+70\right)=445\)
=>\(2x+70=575-445=130\)
=>\(2x=130-70=60\)
=>x=60/2=30
b: \(575-2\left(x+70\right)=445\)
=>\(2\left(x+70\right)=575-445=130\)
=>x+70=130/2=65
=>x=65-70=-5
c: \(x^5=32\)
=>\(x^5=2^5\)
=>x=2
d: \(\left(3x-1\right)^3=8\)
=>\(\left(3x-1\right)^3=2^3\)
=>3x-1=2
=>3x=3
=>\(x=\dfrac{3}{3}=1\)
e: \(\left(x-2\right)^3=27\)
=>\(\left(x-2\right)^3=3^3\)
=>x-2=3
=>x=5
f: \(\left(2x-3\right)^2=9\)
=>\(\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
g: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2\)
=>2x+5=9
=>2x=9-5=4
=>x=4/2=2
h: \(\left(4x-5^2\right)\cdot7^3=7^4\)
=>\(4x-25=\dfrac{7^4}{7^3}=7\)
=>4x=25+7=32
=>\(x=\dfrac{32}{4}=8\)
\(\left(2x+3\right)^3=7^3\)
\(\Rightarrow2x+3=7\)
\(\Rightarrow2x=7-3=4\)
\(\Rightarrow x=4:2=2\)
(2x+3)3=73 \(\Leftrightarrow\)2x+3=7 \(\Leftrightarrow\)x=2