B = 3/5 x 4/3+4/3-3/5 x 4/3
nhanh giúp mình
K
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27 tháng 5 2021
các bạn giải ra từng bước giúp mình, mình đang cần gấp
HN
1 tháng 7 2018
a, \(5\frac{3}{4}:\frac{5}{6}-3\frac{3}{4}:\frac{5}{6}\)
\(=\left(5\frac{3}{4}-3\frac{3}{4}\right):\frac{5}{6}\)
\(=2\frac{3}{4}:\frac{5}{6}\)
\(=\frac{11}{4}.\frac{6}{5}\)
\(=\frac{66}{20}\)
\(=\frac{33}{10}\)
b, \(\frac{4}{5}.\frac{22}{47}+\frac{25}{47}:\frac{5}{4}\)
\(=\frac{4}{5}.\frac{22}{47}+\frac{25}{47}.\frac{4}{5}\)
\(=\frac{4}{5}.\left(\frac{22}{47}+\frac{25}{47}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
1 tháng 7 2018
a) 5\(\frac{3}{4}\) : \(\frac{5}{6}\) - 3\(\frac{3}{4}\) : \(\frac{5}{6}\)
= ( 5\(\frac{3}{4}\) - 3\(\frac{3}{4}\) ) : \(\frac{5}{6}\)
= 2 : \(\frac{5}{6}\) = \(\frac{12}{5}\)
b) \(\frac{4}{5}\) x \(\frac{22}{47}\)+ \(\frac{25}{47}\) : \(\frac{5}{4}\)
= \(\frac{4}{5}\) x \(\frac{22}{47}\) + \(\frac{25}{47}\) x \(\frac{4}{5}\)
= \(\frac{4}{5}\) x ( \(\frac{22}{47}\) + \(\frac{25}{47}\) )
= \(\frac{4}{5}\) x 1 = \(\frac{4}{5}\)
PH
6
15 tháng 8 2019
x/5=2/3:16/21 b)x/10=4/5.3/4 NHỚ K NHÉ MỌI NGƯỜI
x/5=2/3.21/16 x/10=3/5
x/5=7/8 =>x=3.10/5
=>x=5.8/7 =>x=6
=>x=40/7
15 tháng 8 2019
\(\frac{2}{3}:\frac{x}{5}=\frac{16}{21}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}:\frac{16}{21}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}.\frac{21}{16}\)
\(\Rightarrow\frac{x}{5}=\frac{7}{8}\)
\(\Rightarrow x=\frac{7.5}{8}\)
\(\Rightarrow x=\frac{35}{8}\)
Vậy \(x=\frac{35}{8}\)
b) \(\frac{x}{10}:\frac{3}{4}=\frac{4}{5}\)
\(\Rightarrow\frac{x}{10}=\frac{4}{5}.\frac{3}{4}\)
\(\Rightarrow\frac{x}{10}=\frac{3}{5}\)
\(\Rightarrow x=\frac{3.10}{5}\)
\(\Rightarrow x=6\)
Vậy \(x=6\)
Chúc bạn học tốt !!!
30 tháng 7 2018
B=\(\left[\left(\frac{1}{3}+\frac{1}{4}\right)x\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{12}x\frac{12}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\left(\frac{7}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)
B=\(\frac{5}{4}-\frac{1}{4}+2012\)
B=1+2012
B=2013
30 tháng 7 2018
\(B=[\left(\frac{1}{3}+\frac{1}{4}\right)\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{12}\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=[\frac{7}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=1:\frac{4}{5}-\frac{1}{4}+2012\)
\(B=\frac{5}{4}-\frac{1}{4}+2012\)
\(B=1+2012\)
\(B=2013\)
KT
16 tháng 8 2018
1) \(x^4+4=\left(x^2+2\right)^2-4x^2=\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)
2) \(a^4+64=\left(a^2+8\right)-16a^2=\left(a^2+4a+8\right)\left(a^2-4a+8\right)\)
3) \(x^5+x+1\)
\(=\left(x^5-x^4+x^2\right)+\left(x^4-x^3+x\right)+\left(x^3-x^2+1\right)\)
\(=x^2\left(x^3-x^2+1\right)+x\left(x^3-x^2+1\right)+\left(x^3-x^2+1\right)\)
\(=\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)
4) \(x^5+x-1\)
\(=\left(x^5+x^4-x^2\right)-\left(x^4+x^3-x\right)+\left(x^3+x^2-1\right)\)
\(=x^2\left(x^3+x^2-1\right)-x\left(x^3+x^2-1\right)+\left(x^3+x^2-1\right)\)
\(=\left(x^2-x+1\right)\left(x^3+x^2-1\right)\)
KC
26 tháng 6 2018
a, x + \(2\frac{3}{4}\)= \(5\frac{2}{3}\)
= x + \(\frac{11}{4}\)= \(\frac{17}{3}\)
x = \(\frac{17}{3}\)- \(\frac{11}{4}\)
x = \(\frac{35}{12}\)
b , x - \(1\frac{4}{5}\)= \(3\frac{2}{7}\)
= x - \(\frac{9}{5}\)= \(\frac{23}{7}\)
x = \(\frac{23}{7}\)+ \(\frac{9}{5}\)
x = \(\frac{178}{35}\)
c , x * \(\frac{31}{2}\)= \(4\frac{3}{4}\)
= x * \(\frac{31}{2}\)=\(\frac{19}{4}\)
x = \(\frac{19}{4}\): \(\frac{31}{2}\)
x = \(\frac{38}{124}\)= \(\frac{19}{64}\)
d , x : 2 2/? = 4 1/3 câu d thiếu nha bạn
1 tháng 7 2018
\(\frac{3-x}{5}=\frac{1}{4}\)
\(\Rightarrow\left(3-x\right)\cdot4=5\cdot1\)
\(\Rightarrow12-4x=5\)
\(\Rightarrow4x=12-5\)
\(\Rightarrow4x=7\)
\(\Rightarrow x=7:4\)
\(\Rightarrow x=\frac{7}{4}\)
Vậy \(x=\frac{7}{4}\)
NV
1 tháng 7 2018
\(3-\frac{x}{5}=\frac{1}{4}\)
\(\Leftrightarrow\frac{x}{5}=3-\frac{1}{4}\)
\(\Leftrightarrow\frac{x}{5}=\frac{11}{4}\)
\(\Leftrightarrow4x=5.11\)
\(\Leftrightarrow4x=55\)
\(\Leftrightarrow x=55:4\)
\(\Leftrightarrow x=\frac{55}{4}\)
\(\dfrac{3}{5}\times\dfrac{4}{3}+\dfrac{4}{3}-\dfrac{3}{5}\times\dfrac{4}{3}\\ =\left(\dfrac{3}{5}\times\dfrac{4}{3}-\dfrac{3}{5}\times\dfrac{4}{3}\right)+\dfrac{4}{3}\\ =0+\dfrac{4}{3}=\dfrac{4}{3}\)
\(B=\dfrac{3}{5}.\dfrac{4}{3}+\dfrac{4}{3}-\dfrac{3}{5}.\dfrac{4}{3}=\dfrac{4}{3}\)