Tìm x biết:
a) 5 ( x+35)=515
b) (x+40).15=75.12
c) 460+85.4=(x+200):4
Tính nhanh: (23.94+93.45):(92.10-92)
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Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
Ta có: 460+85,4=(x-200):4
suy ra 460+340=(x-200):4
suy ra 800=9x-200):4
suy ra 800:4=x-200
suy ra x=3200+200=3400
ta có 460+85.4=(x-200):4
<->460+340=(x-200):4
<-> 800=(x-200):4
<->800.4=x-200
->x=3200+200=3400
a) 460 + 85 * 4 = ( x + 200 ) * 4
460 + 340 = ( x + 200 ) * 4
800 = ( x + 200 ) * 4
x + 200 = 200
x = 0
b) x + 5 * 2 - ( 32 + 16 * 3 : 16 - 15 ) = 0
x + 10 - ( 32 + 3 - 15 ) 0
x + 10 - 20 = 0
x - 10 = 0
x = 10
a) \(460+85.4=\left(x+200\right).4\)
\(\Rightarrow460+340=4x+800\)
\(\Rightarrow-4x=800-460-340\)
\(\Rightarrow-4x=0\)
\(\Rightarrow x=0\)
Vậy x = 0
b) \(x+5.2-\left(32+16.3:16-15\right)=0\)
\(\Rightarrow x+10-\left(32+3-15\right)=0\)
\(\Rightarrow x+10-20=0\)
\(\Rightarrow x-10=0\)
\(\Rightarrow x=10\)
Vậy x = 10
\(460+85.4=\left(x+200\right):2\)
\(460+340=\left(x+200\right):4\)
\(800=\left(x+200\right):4\)
\(\left(x+200\right):4=800\)
\(x+200=800.4\)
\(x+200=3200\)
\(x=3200-200\)
\(x=3000\)
\(5^x=125\)
\(5^x=5^3\)
Vì \(5=5\)
\(\Rightarrow x=3\)
5x = 125
x = 3
460 + 340 = (x + 200) : 4
800 = (x + 200) : 4
x + 200 = 800 : 4
x + 200 = 200
x = 200 - 200
x = 0
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a. 5(x+35)=515
=> x+35=515:5
=> x+35=103
=> x = 103-35
=> x = 68
b. (x+40).15=75.12
=>(x+40).15=900
=>x+40=900:15
=>x+40=60
=>x=60-40
=>x=20
c.460+85.4=(x+200):4
=>460+340=(x+200):4
=>800=(x+200):4
=>800.4=x+200
=>3200=x+200
=>x=3200-200
=>x=3000
5(x+35)=515
x+35=515/5
x+35=103
x=103-35
x=68