(-1/2*3*4)+( -1/3*4*5)+ ..+( -1/28*29*30)
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Tìm x biết :
\(\frac{1}{1×2×3×4}+\frac{1}{2×3×4×5}+\frac{1}{3×4×5×6}+...+\frac{1}{27×28×29×30}×x=-3\)
Câu 11:
(\(\dfrac{11}{4}\). \(\dfrac{-5}{9}\) - \(\dfrac{4}{9}\).\(\dfrac{11}{4}\)).\(\dfrac{8}{33}\)
= \(\dfrac{11}{4}\).(\(\dfrac{-5}{9}\) - \(\dfrac{4}{9}\)). \(\dfrac{8}{33}\)
= \(\dfrac{11}{4}\).(-1).\(\dfrac{8}{33}\)
= - \(\dfrac{2}{3}\)
30+29+28+.......+2+1=(1+2+3+4+5).x
(30+1)x30:2=15.x
465=15.x
x=465:15
x=31
~shizadon~
Theo bài ra ta có:
30 + 29 + 28 + ... + 2 + 1 = (1 + 2 + 3 + 4 + 5) . x
(30 + 1) x 30 : 2 = 15 . x
x = 465 : 15
x = 31
1: \(=\dfrac{1}{29\cdot30}-\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{28\cdot29}\right)\)
\(=\dfrac{1}{29\cdot30}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{28}-\dfrac{1}{29}\right)\)
\(=\dfrac{1}{29\cdot30}-\dfrac{28}{29}=\dfrac{1-28\cdot30}{870}=\dfrac{-859}{870}\)
S = 1 * 2 + 2 * 3 + 3 * 4 + ...... + 28 * 29 + 29 * 30
3S = 1 x 2 x 3 - 1 x 2 x 3 + 2 x 3 x 4 - 2 x 3 x 4 + .............. + 29 x 30 x 31
3S = 29 x 30 x 31
S = 29 x 30 x 31 : 3 = 8990
Ta có : S = 1.2 + 2.3 + 3.4 + ..... + 28.29 + 29.30
<=> 3S = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ...... + 29.30.31
<=> 3S = 29.30.31
<=> S = 29.30.31 / 3 = 8990
Chúc học tốt nhé !
Ta có
30 + 29 + 28 + 27 + ... + 2 + 1 = (1 + 2 + 3 + 4 + 5).x
(30.31):2 = 15.x
465 = 15x
x = 465 : 15
x = 31
Vậy x = 31 là giá trị cần tìm
Theo bài ra ta có:
30 + 29 + 28 + ... + 2 + 1 = (1 + 2 + 3 + 4 + 5) . x
(30 + 1) x 30 : 2 = 15 . x
x = 465 : 15
x = 31
1 + 2-3-4+5+6-7-8+9+...+28-29-30+31 + 32
= 1 + (2-3-4+5) + (6-7-8+9) + ...+(28-29-30+31) + 32
= 1 + 0+0+...+0+32
= 1+32
=33
1+2-3-4+5+6-7-8+9+...+28-29-30+31+32?
( 1 + 2 - 3 - 4 ) + ( 5 + 6 - 7 - 8 ) + ...... + ( 29 + 30 - 31 - 32 )
= 0 + 0 + ....+ 0
= 0
\(B=\frac{1}{1.2.3.4}+\frac{1}{2.3.4.5}+...+\frac{1}{27.28.29.30}\)
\(=\frac{1}{3}\left(\frac{1}{1.2.3}-\frac{1}{2.3.4}+\frac{1}{2.3.4}-\frac{1}{3.4.5}+....+\frac{1}{27.28.29}-\frac{1}{28.29.30}\right)\)
\(=\frac{1}{3}\left(\frac{1}{1.2.3}-\frac{1}{28.29.30}\right)\)
\(=\frac{1}{3}\left(\frac{1}{6}-\frac{1}{24360}\right)\)
\(=\frac{1}{3}.\frac{1353}{8120}=\frac{451}{8120}\)
to hoc lop 4 nen khong biet nhin chang hieu gi het tron nhe moi nguoi thong cam cho minh nhe chu to khong biet m cu bat to biet a ulatr
A = \(\dfrac{-1}{2.3.4}-\dfrac{1}{3.4.5}-...-\dfrac{1}{28.29.30}\)
A = - \(\dfrac{2}{2}\).(\(\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{28.29.30}\))
A = - \(\dfrac{1}{2}\).(\(\dfrac{2}{2.3.4}+\dfrac{2}{3.4.5}+...+\dfrac{2}{28.29.30}\))
A = -\(\dfrac{1}{2}\).(\(\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{28.29}-\dfrac{1}{29.30}\)
A = \(-\dfrac{1}{2}\).(\(\dfrac{1}{2.3}\) - \(\dfrac{1}{29.30}\))
A =- \(\dfrac{1}{2}\).(\(\dfrac{1}{6}\) - \(\dfrac{1}{870}\))
A = - \(\dfrac{1}{2}\).\(\dfrac{24}{145}\)
A = -\(\dfrac{12}{145}\)